The oxydation state for S in (SO4)2- is 6.
Only Ba2+ and SO42- react, while Na+ and Cl- don't.Ba2+ + SO42- --> (BaSO4)s
In this ion the oxidation state of sulfur is 6+ and the oxidation state of each oxygen is 2-
which halogen naturally exit in + ve oxydation state
I'm pretty sure it's -2 because everywhere i look i find the chemical formula as being NaHCO3 and if you add up those oxidation numbers then you get -2.
Since iron (Fe) is more reactive than copper (Cu) it will be 'plated' with copper when the metal iron is stuck in copper sulfate solution. Fe(s) + Cu2+(aq) + [SO42-]aq ---> Fe2+(aq) + Cu(s) + [SO42-]aq
SO42- (our goal is to get -2 charge) Oxygen by default has a -2 oxidation number, and we have 4 total, -2 X 4 = -8, our goal is -2, so S is +6.
As SO42- has an overall -2 charge, The Oxygen has a -2 oxidation state, so to balance and give an overall -2 charge, the Sulfur has to have a +6 oxidation state. (-2 x 4) + (s) = -2 s = +6
Only Ba2+ and SO42- react, while Na+ and Cl- don't.Ba2+ + SO42- --> (BaSO4)s
In this ion the oxidation state of sulfur is 6+ and the oxidation state of each oxygen is 2-
which halogen naturally exit in + ve oxydation state
The sulfate ion is SO42 -. The oxidation state of the sulfur is +6 (work it out!); therefore, the ion is more properly named the sulfate(VI) ion. The sulfite ion is SO32-. The oxidation state of the sulfur is +4.
The sulfate ion is SO42 -. The oxidation state of the sulfur is +6 (work it out!); therefore, the ion is more properly named the sulfate(VI) ion. The sulfite ion is SO32-. The oxidation state of the sulfur is +4.
Yes: Cu(OH)2(s) + 2H+(aq) + [SO42-(aq)] --> Cu2+(aq) + 2H2O(l) + [SO42-(aq)]
NH4+ and Cl- don't react, Only SO42- and Ba2+ do so by forming precipitate: SO42- + Ba2+ --> (BaSO4)s
2Na+(aq) + SO42-(aq) + Ca2+(aq) + 2Cl-(aq) CaSO4(s) + 2Na+(aq) + 2Cl-(aq)
NH4+ and NO3- don't react, Only SO42- and Ba2+ do so by forming precipitate: SO42- + Ba2+ --> (BaSO4)s
I'm pretty sure it's -2 because everywhere i look i find the chemical formula as being NaHCO3 and if you add up those oxidation numbers then you get -2.