The sulfate ion is SO42 -. The oxidation state of the sulfur is +6 (work it out!); therefore, the ion is more properly named the sulfate(VI) ion. The sulfite ion is SO32-. The oxidation state of the sulfur is +4.
If you mean SO3^-2 (the sulfite anion), then S has an oxidation number of 4+, since each O atom is 2-. In sulfur trioxide, SO3, the S atom has an oxidation number of 6+.
+6 oxidation state
S is +6, O is -2
-2 for each O +6 for S
-2 for each O +6 for S
If you mean SO3^-2 (the sulfite anion), then S has an oxidation number of 4+, since each O atom is 2-. In sulfur trioxide, SO3, the S atom has an oxidation number of 6+.
+6 oxidation state
S has an oxidation state of +4 in a sulfite anion as stated. In oxyanions, oxygen always has an oxidation state of -2. Therefore, three oxygen atoms will have total oxidation number of -6, requiring an oxidation number of +4 for sulfur to sum to the charge of -2 on the anion as a whole.
S has an oxidation state of +4 in a sulfite anion as stated. In oxyanions, oxygen always has an oxidation state of -2. Therefore, three oxygen atoms will have total oxidation number of -6, requiring an oxidation number of +4 for sulfur to sum to the charge of -2 on the anion as a whole.
S is +6, O is -2
-2 for each O +6 for S
-2 for each O, +6 for S
-2 for each O +6 for S
Things are complicated if we use the term valency. It is better to use the term Oxidation state or Oxidation Number. In SO2, the oxidation state of sulphur is +4 and In SO3, the oxidation state of sulphur is +6.
That depends on the compound that it is in but it is often found in the oxidation states 2-, 4+, and 6+. In its elemental for the oxidation state is 0, which is true of all elements. In sulfides, thiols, and similar compounds such as H2S, K2S, CH3SH and HSCN it s int the 2- oxidation state. In sulfur dioxide (SO2) and sulfites such as Na2SO3 and SrSO3 it is in the 4+ oxidation state. In sulfur trioxide (SO3), sulfuric acid (H2SO4), and sulfates such as MgSO4, K2SO4, and NaHSO4 it is in the 6+ oxidation state..
Oxidation state of O is -2.Oxidation state of S is +4.
S = +4 oxidation state O = -2 oxidation state