0
ph = LOG[OH-]
so....
Ph= LOG[0.170]
=0.76955
H+OH = 14 so
14- 0.76955 = 13.23
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∙ 10y ago
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How should the pH of a 0.1 molar solution of nac2h3o2 compare with that of a 0.1 molar solution of kc2h3o2?
the PH will be the same
PH of 0.1M NaOH?
The pH value for this solution is 13.
What is the PH for 0.002M solution of NaOH?
11.3
What has a pH of 13.0?
A 0.01 M solution of NaOH has a pH =13
What is the pH of a 10-4 M naoh solution?
-log(10^-4 M NaOH) = 4 14 - 4 = 10 pH NaOH -----------------------
How should the pH of a 0.1 molar solution of nac2h3o2 compare with that of a 0.1 molar solution of kc2h3o2?
the PH will be the same
PH of 0.1M NaOH?
The pH value for this solution is 13.
What is the PH for 0.002M solution of NaOH?
11.3
What has a pH of 13.0?
A 0.01 M solution of NaOH has a pH =13
What is the pH of a 10-4 M naoh solution?
-log(10^-4 M NaOH) = 4 14 - 4 = 10 pH NaOH -----------------------
A 0.361 molar solution of the weak acid HA with a pKa of 4.039 is titrated with a 0.163 molar solution of NaOH. What is the pH of the solution at the equivalence point of this titration?
You need to know the volume of the weak acid being titrated so you can find how many moles of base are needed to match that of the acid.
What is the pH of a 0.33 M solution of NaOH?
13.51
What is the pH value of dil NaOH solution?
13
Is there a molar mass of 4.0 PH buffer?
Ph gives the hint about the proton gradient of the solution as pH=-log[H+] we need the inforamtion of the molecular composition of the solution to know about the molar mass. Ph gives the hint about the proton gradient of the solution as pH=-log[H+] we need the inforamtion of the molecular composition of the solution to know about the molar mass.
What has a pH of 13?
concentrated solution of NaOH and KOH have the pH value about 13.
Which has higher pH value 1M HCl or 1 M NaOH solution?
THE PH VALUE ACIDIC SOLUTION VARIOUS FROM 0-6.9, WHILE THE BASIC SOLUTION VARIOUS FROM 7.1-1.4. THUS ,OUT OF HCL AND NaOH WILL HIGHER PH VALUE
What is the pH of a 0.280 molar HCl solution?
pH = -log(0.280) = 0.553
