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What is the percent composition by mass of oxygen in Ca OH 2?


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Answered 2016-06-10 16:48:21

In Ca(OH)2 there is 1 Ca, 2 O, and 2H
Ca = 40 g
O = 16 x 2 = 32
H = 1 x 2 = 2
Total mass = 40 + 32+ 2 = 74 g
%O by mass = 32/74 (x100) = 43.2%

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Answered 2016-07-01 20:03:34

The percentage composition by mass of oxygen in Ca(OH)2 is 43,24 %.

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Answered 2016-07-09 15:36:58

Oxygen accounts for 43.2%.

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The percent composition by element of Ca(C2H3O2)2 is calcium 25.339%, hydrogen 3.824%, carbon 30.375%, and oxygen 40.462%.


Percent CompositionFirst you have to find all the atomic masses of the elements involved in the compound. Then you have to add them up to get the total molecular mass. Take the atomic mass of Ca and divide it by the total mass. Multiply it by 100 and you will get the percent of Ca in any compound of Ca(OH)2. Once you know the percent composition, you can take Ca's percent from the whole sample. Ca: 40.1O: 16.0×2 = 32.0H2: 1.0×2 = 2.0Ca(OH)2: 74.1 grams(40.1 ÷ 74.4) × 100 = 53.9 % of Ca in Ca(OH)253.9 % of 5.00 grams = 2.67 grams of Ca in Ca(OH)2


Ca=40, Ba=80, so CaBr2 = 40+80+80=200. Calcium's part is 40/200=20%, bromine's part is 160/200=80%.


how can you get 12 percent CaO from CaCl2


CaCO3 Ca=Calcium C=Carbon O=Oxygen



It would seem that because calcium and oxygen are in equal molar ratio for this compound that it would be 50 percent. But that is incorrect, because they each have differing molar masses. Oxygen has a molar mass of 16.000 and calcium has a molar mass of 40.078. So calcium is 40.078/56.078, which is 71.47 percent.



Here you go Molar mass of CaSO4 = 136.1406 g/molMolecular weight calculation:40.078 + 32.065 + 15.9994*4ElementSymbolAtomic Mass# of AtomsMass PercentCalcium Ca 40.078 1 29.439%


The total mass of the compound is 20.0 + 16.0 = 36.0. The percentage of Ca is the mass of the Ca over the total mass, so it's 20.0/36.0 = 0.556


Calcium nitrate Step 1: Determine the total mass of each element in the molar mass 1 mol Ca x (40.08gCa/1 mol Ca) = 40.08 g Ca 2 mol N x (14.01gN/1 mol N) = 28.02 g N 6 mol O x (16.00gO/1 mol O) = 96.00 g O 1 mol of Ca(NO3)2 = 164.1 g (molar mass) Step 2: Calculate percent by multiplying the mass ratio by 100% %Ca = (40.08gCa/164.1 Ca(NO3)2) x 100 = 24.42% %N = (28.02gN/164.1 Ca(NO3)2) x 100 = 17.07% %O = (96.00gO/164.1 Ca(NO3)2) x 100 = 58.50%


The total mass of CaSO4 is 136.139 g/mol. - The mass of Ca is 40.078, so % comp is 40.078/136.139 x 100 = 29.4% - The mass of S is 32.065 so % comp is 23.56%, using the method above - The mass of O is 15.999, but because there are four O atoms in the compound, the % comp will be (15.999 x 4) / 136.139 x 100 = 47.0%


Average atomic mass of Ca = 40.1 Average atomic mass of O = 16.0 Mr(Ca)/Mr(O) = 40.1/16.0 = 2.51 Thus the calcium atom is about 2.5 times heavier than the oxygen atom.


Molecular mass of calcium oxide = calcium (40,078) + oxygen (15,9994) = 56,0774 56,0774 CaO--------------40,078 Ca 100 g CaO-----------------x g Ca x = (40,078 x 100)/56,o774 = 71,469 % Ca


Atomic mass of calcium, Ca = 40.1Mass of 1 mole of Ca is 40.1gMass of 3.00 moles of Ca = 3 x 40.1 = 120.3g


Ca has an RAM of 40. Cl has an RAM of 35.5. Therefore CaCl2 = 40 + 2(35.5) = 40 + 71 = 111. the % of Ca in CaCl2 is equal to 40/111 x 100.


For this you need the atomic mass of Ca. Take the number of moles and multiply it by the atomic mass. Divide by one mole for units to cancel. Ca= 40.1 grams.761 moles Ca × (40.1 grams) = 30.5 grams Ca


1 mole Ca = 40.78g (atomic weight in grams)


Assume the compound has a molar mass of 100 grams, from the information given, 32.2 grams is Calcium and 67.8 grams is Nitrogen.You then find the moles of each, which would be moles of Ca and moles of N.Dividing the two moles gives you the mole fraction: which we approximate to 6. This means that for every 1 mole of Ca, there are 6 moles of N, thus the answer is


Ca is Calcium, C is carbon, and O is oxygen


The mass is 0.330 mol Ca (40.08 g/mol) = 13.2 g Ca


Same structure but different composition ex. Ca F2 - BaCl2


The mass of 3,400 mol Ca(OH)2 is 251,9 g.


Divide the mass of Ca by the overall mass of the pill. 1.35g/2.36g then multiply answer x 100. The answer is 57.2% (3 sig figs)


If you trhink to calcium hydroxide - Ca(OH)2 - this mass is 148,086 g.



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