Potassium carbonate has 8,69 % carbon and 8,6 g K2CO3 have 0,75 g carbon.
To determine the amount of K2CO3 in a 10% solution, you need to know the total volume of the solution. For example, if you have 1000 mL (1 liter) of the 10% solution, it means there are 100 grams of K2CO3 in that solution. This is because 10% of 1000 mL is 100 grams.
The density of potassium carbonate (K2CO3) is approximately 2.43 grams per cubic centimeter.
For carbon 0.80 x 100 = 80 grams of carbon; and for hydrogen 0.20 x 100 = 20 grams of hydrogen
To prepare a 0.50 by volume (v/v) K2CO3 solution, you need 0.50 liters of K2CO3 per 100 mL of solution. For 150 mL, this means you need 0.75 mL of K2CO3. The density of K2CO3 is approximately 2.43 g/cm³. Therefore, the mass of K2CO3 needed is calculated as follows: 0.75 mL × 2.43 g/mL = 1.83 grams.
Weight:1.45 grams volume: 6.789
To calculate the percent weight (weight/weight percent) of a solution, you use the formula: [ \text{Percent Weight} = \left( \frac{\text{mass of solute}}{\text{mass of solute} + \text{mass of solvent}} \right) \times 100 ] In this case, you have 50 grams of solute and 1000 grams of solvent, so the total mass is 50 + 1000 = 1050 grams. Therefore, the percent weight is: [ \left( \frac{50}{1050} \right) \times 100 \approx 4.76% ]
12.01 grams per mole
The molecular weight of carbon is 12.0107 g/mol, or grams per molecule. This is calculated by dividing the total weight of the atom by the weight of all the atomic mass units and multiplying by 100.
moles = weight in grams / molecular weight = 56 / 28 = 2 moles
Since 2 moles H2O weight 36 grams: this is the answer.
It is approximately 24.02 grams. Each mole of carbon weights 12.01 grams (one mole= enough particles to make a substance's weight in grams equal to it's atomic weight in amu; same amount of particles for every substance).
First, calculate the number of moles of K2CO3 in 10.0 grams. Next, write and balance the chemical equation for the reaction between HCl and K2CO3. Use the stoichiometry of the balanced equation to determine the number of moles of HCl required to react with the moles of K2CO3. Finally, use the molarity of the HCl solution to calculate the volume needed.