10g of K2CO3 in 100mL
600ml.
10% of 6L is 600 ml. 6000 / 100 * 10 = 600 ml.
The mass of sugar is 100 g.
percent concentration = (mass of solute/volume of solution) X 100 To solve for mass of solute, mass of solute = (percent concentration X volume of solution)/100 So, mass of solute = (10% X 100mL)/100 = 10g
Make an equation: x(.10) = 50gal(.15) Solve algebraically: x = 75 gal
10 liters
10
600ml.
16 2/3 liters
add 4 parts water per part solution
10% of 6L is 600 ml. 6000 / 100 * 10 = 600 ml.
4 ml
10 gallons..
10 liters.
true
6 litres of 50% + 4 litres of 25%
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