MnSO4 aplications in Agriculture
I must have the same sheet as you as I have the exact same question. Okay, The RFM of Manganese (Mn) is 54.9 The RFM of MnSO4 4H20 is 223 The percentage of Mn in MnSO4 4H2O is 54.9/223 X 100 and that is 24.6 % 0.1 Moles of MnSO4 4H20 is 223/100 X10 = 22.3 24.6 % (percentage of Mn in MnSO4 4H2O) of 22.3 (0.1 Moles of MnSO4 4H2O) is 5.49g Then you do 5.49g/54.9g (RFM of Mn) which is 0.1 Moles of Mn, which is your answer.
MnSO4 is the only one that directly reacts with O2 at BOD?With alkaline: MnSO4 + 2OH = MnOH2 +SO44Mn(OH)2 + 2 H20 + O2 = 4 Mn(OH)3
Mn(s) + H2SO4(aq) ------> MnSO4(aq) + H2(g) [molecular] Mn(s) + 2H+(aq) -----> Mn2+(aq) + H2(g) [net ionic]
Manganese(II) Fluoride = MnF2Manganese(III) Fluoride = MnF3Manganese(IV) Fluoride = MnF4
The chemical equation is:Al2(SO4)3 + 3 Mn = 2 Al + 3 MnSO4
MnSO4+Na2CO3
For the anhydrous MnSO4 the mass is 167,61 g.
Well Mn stands for Maganese. S is for Sulfur. Then O is obviously Oxygen. That means Mn only has one, Sulfur has one. Oxygen would have 4 and they would get rid of 4 electrons so that would leave you a negative bond.
MnCrO4 is manganese(II) chromate
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Manganese sulfate has an ionic bond.