equation for time in pendulum:
t = 2 * pi * ( sq. root (l / g))
key:
t = time elapsed ( total, back and forth )
l = length , from pivot to centre of gravity
g = acceleration due to gravity
say 1 metre length pendulum on earth @ 9.82 (m/s)/s, t = 2.005 seconds
same pendulum on neptune @ 11.23 (m/s)/s, t = 1.875 seconds
Earth is small compared to Neptune
Neptune has a gravity that is about 1.14 that of Earth.
Neptune is 34 times bigger then earth
Not compared to earth!
The rotation period of Neptune is 16.1 earth hours.
Neptune are 164.79 years compared to earth
Earth is small compared to Neptune
Neptune has a gravity that is about 1.14 that of Earth.
Neptune is 34 times bigger then earth
At the center of the Earth there would be no effective gravity; a pendulum wouldn't work as a pendulum.
Not compared to earth!
Approx 80.5 centimetres.
... dependent on the length of the pendulum. ... longer than the period of the same pendulum on Earth. Both of these are correct ways of finishing that sentence.
The period of a simple pendulum swinging at a small angle is approximately 2*pi*Sqrt(L/g), where L is the length of the pendulum, and g is acceleration due to gravity. Since gravity on the moon is approximately 1/6 of Earth's gravity, the period of a pendulum on the moon with the same length will be approximately 2.45 times of the same pendulum on the Earth (that's square root of 6).
Nice problem! I get 32.1 centimeters.
Infinite
you have to times it's mass