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It depends on the starting phase, but it would be equal to the voltage.

Resistive circuit don't change phase only inductive/capacitive circuits do. For a simple/ideal circuit the phase would be zero. In reality (with three phase power) it would be 0,120,-120 depending on which line your drawing power from and whether it is truly a pure resistive circuit.

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Phase angle is defined as the angle by which the load current leads or lags the supply voltage (not the other way around!). For a purely-resistive circuit, the load current is in phase with the supply voltage. For a resistive-inductive circuit, the load current lags the supply voltage by some angle. For a resistive-capacitive circuit, the load current leads the supply voltage by some angle.

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12y ago
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13y ago

First determine what kind of load is creating the angle: xl-xc squared. Not going to show calculations obviously you have some reference material.

L dominate will be + angle and C will be -.

use right triangle math put R or P or any non reactive value on bottom of triangle, put dominant reactive value on verticle, calculate angle =hyp-1 opp/adj. Remember to put - in front of angle if xc greater than xl.

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11y ago

It's usually 68 degrees. Plus or minus 1.

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If you are referring to the difference between an 'ideal' transformer's primary voltage and the resulting flux in the core of that transformer, then the voltage leads the flux by 90 degrees.

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12y ago

As the voltage increases or decreases depending where it's timing is in the wave, the current will increase or decrease in direct relation to the timing of the wave as well.

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The phase angle between voltage and current in a purely resistive circuit is zero. Voltage and current are in phase with each other.


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