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HA ==> H+ + A-Ka = [H+][A-][HA] and from pH = 2.31, calculated [H+] = 4.89x10^-3 M
Ka = (4.89x10^-3)(4.89x10^-3)/0.012
Ka = 1.99x10^-3
pKa = 2.70
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How can you calculate pka valve if pH is given?
How can you calculate pka valve if ph is given?
What would be the pH at the half-equivalence point in titration of a monoprotic acid with NaOH solution if the acid has Ka equals 5.2x10-6?
At 'half way' point the pH is equal to the pKa value of the acid: pH = pKa - log[cA/cB] because at that point cA = cB . So pH = pKa = - log(5.2*10-6) = 5.3
What does pH of a solution depend on?
The molarity. The hydrogen ion concentration. If given the Ka just use the Henderson-Hasselbach equation pH=pKa+log(base/acid)
What does pH of the solution depend on?
The molarity. The hydrogen ion concentration. If given the Ka just use the Henderson-Hasselbach equation pH=pKa+log(base/acid)
How you can select buffer in hplc according to pka value?
By following + or - 2 pH to the pKa value
What is the pka of .012M solution and a pH of 2.31?
HA ==> H+ + A-Ka = [H+][A-][HA] and from pH = 2.31, calculated [H+] = 4.89x10^-3 M Ka = (4.89x10^-3)(4.89x10^-3)/0.012 Ka = 1.99x10^-3 pKa = 2.70
What is definition of pka value and difference between pH and pKa?
A pKa value is a measurement used for bases and acids. The measurement pH applies to hydronium ion concentrations that are in a solution, whereas pKa only applies to determining the amount of dissociation an acid wants to do in a solution.
The pH of ethanol?
the pH of ethanol can be calculated using its pKa value (pKa 15.9) and the Henderson-Hasselbalch equation. pH = pKa - log [AH/A] where [AH/A] the ratio of disassociated versus undisassociated species in solution.
What pH of pka is 5.4?
This question does not make very much sense but it will somewhat be answered. PH is the measurement of a concentration of hydronium ions in a solution. PKA is the measurement of how much is available. If the concentration and pka of a substance is known, the pH can be calculated.
How do you get pKa with the pH of a solution?
pKa= pH - log(A/HA) to clarify -log is subtract log E.g A buffer is prepared by adding .15 M of NaOH and .1 of a weak acid, HA. If the pH of the buffer is 8.15, what is the pKa of the acid? pH= 8.15 - log .15/.1 = 7.97
What is Henderson-Hasselbalch equation?
Its an equation you can use to find the pH of a solution. it is.... --- pH = pKa + log (Base/Acid) --- these may help too Ka = 10^-pKa Kw = Ka*Kb
Effect of Diluting a buffer?
The buffer capacity increases as the concentration of the buffer solution increases and is a maximum when the pH is equal to the same value as the pKa of the weak acid in the buffer. A buffer solution is a good buffer in the pH range that is + or - 1 pH unit of the pKa. Beyond that, buffering capacity is minimal.
When is a buffer solution most effective?
It is the most effective when it is at pH=pKa of its weak acid component.
What is the pH for 1M Na2C4H2O4?
The ph. for this 1M Na2C4H2O4 solution can be found using the kA and the equation pH = pKa + log([base]/[acid]) This salt Na2C4H2O4 is going to increase the concentration of base in the solution.
How can you calculate pka valve if pH is given?
How can you calculate pka valve if ph is given?
How do you calculation pH from ka?
Ka = [H+][A-] / [HA] Hence [H+] = Ka[HA] / [A-] Remember pH = -log(10)[H+] 'logging' both sides. -log(10)[H+] = - log(10)Ka[HA] / [A-] By algebraic manipulation of log. pH = -log[A-]^-1 - logKa - log[HA] pH = log[A-] - logKa - log[HA] pH = pKa - log[HA]/[A-]
What would be the pH at the half-equivalence point in titration of a monoprotic acid with NaOH solution if the acid has Ka equals 5.2x10-6?
At 'half way' point the pH is equal to the pKa value of the acid: pH = pKa - log[cA/cB] because at that point cA = cB . So pH = pKa = - log(5.2*10-6) = 5.3
