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What is the power consumed in a 10 k ohm resistor due to a periodic synusoidal current of maximum magnitude 90 mA passing through it?
Wiki User
∙ 12y ago
P=IE
What voltage (E) will be dropped across the resistor? Current (I) = .090 A
Assuming 90 VAC dropped across the resistor, then P=90 x .090 which = 8.1 Watts.
Wiki User
∙ 12y ago
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