The electronic configuration of Bromine in its ground state is:
1s2 2s2p6 3s2p6d10 4s2p5.
Therefore the principal quantum number for the outermost electrons in a Bromine atom is 4.
It is n=4 because Br is in the 4p valence shell.
5
ms -1/2
M1 = -1
It goes by valence electrons. The configuration of Sulfur is: 1s2 2s2 2p6 3s2 3p4. Sulfur has 6 valence the electrons in the 3s and 3p oribitals. So the principal quantum number, which is denoted by n, is equal to 3. Thus n=3 is for sulfur.
It is n=4 because Br is in the 4p valence shell.
The second quantum number (l) for the electrons in the 4 p energy sublevel of bromine would be 1.
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The principal quantum number of electrons has the symbol n.This number is always an integer.
is the answer 32 electrons
l = 1
18
dont now
ms -1/2
ms -1/2
M1 = -1
There are two valence electrons in Ca. To determine this write out the electronic configuration of Ca using the Principal quantum number method K L M N 2 8 8 2 as you can see the number of electrons in the outermost shell (which is the valency) is 2. Making Ca a metal and giving away its 2q outermost electrons to attain a stable electronic configuration.