5
Nitrogen (N) has atomic number 7, so the electron configuration is 1s2 2s2 2p3. The outermost energy level is level 2 (n=2) so there are a total of FIVE electrons in the outermost energy level.
The electronic configuration of Bromine in its ground state is: 1s2 2s2p6 3s2p6d10 4s2p5. Therefore the principal quantum number for the outermost electrons in a Bromine atom is 4.
It is n=4 because Br is in the 4p valence shell.
ms -1/2
It goes by valence electrons. The configuration of Sulfur is: 1s2 2s2 2p6 3s2 3p4. Sulfur has 6 valence the electrons in the 3s and 3p oribitals. So the principal quantum number, which is denoted by n, is equal to 3. Thus n=3 is for sulfur.
Nitrogen (N) has atomic number 7, so the electron configuration is 1s2 2s2 2p3. The outermost energy level is level 2 (n=2) so there are a total of FIVE electrons in the outermost energy level.
An azimuthal quantum number is a quantum number which represents the angular momentum of an atomic orbital.
An azimuthal quantum number is a quantum number which represents the angular momentum of an atomic orbital.
The electronic configuration of Bromine in its ground state is: 1s2 2s2p6 3s2p6d10 4s2p5. Therefore the principal quantum number for the outermost electrons in a Bromine atom is 4.
Azimuthal quantum number
Azimuthal quantum number
34 azimuthal quantum number
By azimuthal quantum numbers.
It is represented by l.
For a principle quantum number 3, there are three possible sub-shells. These are 3s, 3p, 3d. Azimuthal quantum no. is less than principle quantum number. There for 3s it is 0, for 3p it is 1, for 3d it is 2.
the answer is "no".
All four quantum numbers i.e principle ,azimuthal or subsidiary, magnetic and spin quantum numbers are required to specify a single atomic orbital.