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75%
75%
depends if the black fur gene is dominant.. if it is... then yu would cross BB with bb making all heterozygous genotypes(Bb) therefore, having all possible offspring with black fur so theres a 100% probability of offspring with black fur(:
The answer depends on how big the litter is: as the litter size increases the probability of one black fur increases. But as it gets larger still, the probability falls because two or more black furs become more probable.
There different genotypes and two different colors Black fur is dominant --> F White fur is recessive --> f The parents are bot Ff (heterozygotes, and because black fur is dominant they have a black fur). If they mate, you get parents: Ff x Ff Offspring: FF Ff Ff ff so 25% will be homozygous for Black fur 2x25=50% will be heterozygous, and have a Black fur and 25% wil be homozygous for White fur. Hence, of their offspring, 75% will have a black fur and 25% will have a white fur
Darkening of the fur.
no thats fine its just its fur growing. do not worry!
If brown fur is a dominant trait in the offspring's parents, then approximately 75% of the offspring will most likely have brown fur. This is because there is a 75% chance that each offspring will inherit at least one dominant brown fur gene from the parents.
100% because BB is dominant over bb and all the crosses make Bb
Punnett Squares are useful because they allow you to see the chance of what genes will be handed down to the offspring. They are a quick and easy way to determine the chance of a offspring having a certain characteristic
American red squirrel
i think they would have 50/ chance that it has have fur.