Ch3coo(-) + h2o ---> ch3cooh + oh(-)
CH3CH2OOCCH3 + H2O ===> CH3CH2OH + CH3COOH
Dissolving in water = splitting in ionsCH3COONH4 --> CH3COO- + NH4+CH3COO-, acetate is a weak base: CH3COO- + H2O CH3COOH + OH-NH4+, ammonium is a weak acid: NH4+ + H2O NH3 + H3O+Totally in water: CH3COO- + NH4+ CH3COOH + NH3 and 2H2O H3O+ + OH-
What is the balanced equation for Ch3COOH alone
CH3COOH contains 8 atoms. Two carbon, two oxygen, and four hydrogen.
CuCl2 is the product.
Ch3cooch2ch3 + h2o
It would produce a solution of acetic acid.
its balanced
CH3COOH + AgNO3
There are ten hydrogen atoms in 14.8g of C2H520(Diethyl Ether).
The compound (C2H5)2O is called diethyl ether. It is a type of organic compound that is incredibly flammable and colorless.
Methyl acetate (or Methyl Ethanoate) and water.CH3OH + CH3COOH -----> CH3(CH3COO) + H2O
CH3CH2OOCCH3 + H2O ===> CH3CH2OH + CH3COOH
CH3COOH + OH- ------> H2O + CH3COO- so it is still an acid plus base gives an acetate salt plus water.
Acetic Acid, CH3COOH, has a molecular weight of 60.05
what are the major product formed when ethanol reacts with acidified kmno4 solution
The answer is CH3COOK+H2O. A double replacement reaction means that you would need to figure out what is being swapped. Think of it like this: AB+CD --> AC+BD KOH is a base, which separates into K+ and -OH in solution; likewise CH3COOH (an acid) separates into CH3COO- and H+. The double replacement product couples K+ and CH3COO- together, and coupling H- with -OH to form H2O (water). Good luck.