2 S2O32- + I2 --> S4O62- + 2 I-
thiosulfate + iodine -> tetrathionate* + iodide
* -O3=-=S-S-S-S=-=O3-
Chlorine gas oxidizes some of the iodide ions in the paper to create iodine diatomic molecules. These molecules react with the iodide ions and the starch to form a charge-transfer complex, which has a striking blue color. It is thought that linear I3- and I5- ions occupy the center of the helix structure in the starch. These ions are formed by the reaction of molecular iodine with iodide ions.
Iodide ions reacts with Chlorine to form elementary Iodine and Chloride ions
The chlorine is reduced to chloride ions and the iodide {note correct spelling} are reduced to elemental iodine.
KI reacts with Cu2+ ions and then the CuI2 formed dicomposes to give insoluble CuI salt and I2. The iodine makes the solution brown. Cu2+ + 2I− → CuI2 2 CuI2 → 2 CuI + I2 Sodium thiosulfate can be added to this mixture. It reacts with the iodine giving a white ppt in a colourless solution.
S2O32-(aq) + 2H+(aq) ---> S(s) + SO2(g) + H2O(l)
KI is potassium iodide, you'd react it with something to produce iodine ions. It reacts as reducing agent
The cation is K+ and the anion is I-.
Lithium is a highly reactive metal, so it can react with many other ions, especially halogens such as fluorine, chlorine, bromine, and iodine
Chlorine gas oxidizes some of the iodide ions in the paper to create iodine diatomic molecules. These molecules react with the iodide ions and the starch to form a charge-transfer complex, which has a striking blue color. It is thought that linear I3- and I5- ions occupy the center of the helix structure in the starch. These ions are formed by the reaction of molecular iodine with iodide ions.
Iodide ions reacts with Chlorine to form elementary Iodine and Chloride ions
Ba2+(aq) + SO42-(aq) --> BaSO4(s) The other ions, Cu2+ and Cl-, don't react (tribune ions).
The microbicidal effectiveness of pharmaceutical iodophor preparations comprising an organic substance which reacts with iodine to form a complex thereof, such as polyvinylpyrrolidone, iodine bound thereto in complex form, free iodine, and iodide ions, is assured by controlling the ratio of total iodine (complex bound iodine and free iodine) to iodide ions at between 2:1 and 10:1, this ratio being adjusted without chemical oxidizing agents such as iodate ions by anodic oxidation of a solution of the iodophor preparation and iodide ions. The resulting preparation can be free of chemical oxidizing ions such as iodate ions
Magnesium and iodine react to form the ionic compound magnesium iodide - MgI2.
KI reacts with Cu2+ ions and then the CuI2 formed dicomposes to give insoluble CuI salt and I2. The iodine makes the solution brown. Cu2+ + 2I− → CuI2 2 CuI2 → 2 CuI + I2 Sodium thiosulfate can be added to this mixture. It reacts with the iodine giving a white ppt in a colourless solution.
The chlorine is reduced to chloride ions and the iodide {note correct spelling} are reduced to elemental iodine.
3 ions, 1 of Calcium and 2 of Iodine
Iodine ion is not consumed; in the first step the iodine ion is oxidized to iodine, in the second step iodine is reduced to iodine ion.