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Since the reaction is first order with respect to H2, if the concentration of H2 were halved, the rate of the reaction would be halved. This can be seen by entering one for each value in the rate equation, then changing the value of [H2] to 1/2 while keeping the other values the same: The rate changes from 1 to 1/2.
In a zero order overall process, the rate and rate constant will be the same. (Reaction order is an exponent, and if that exponent is "0" then the value is "1" and will cancel out.)
The rate constant include all parameters ((but not concentration) affecting the rate of a chemical reaction.The expression "specific reaction rate" is used when the molar concentration of reactants is a unit.
As far as I know, No. A negative order means a higher concentration of the reactant having a lower reaction rate. For example: concentration of A reaction rate ---- 4 M .1 M/s 1 M .4 M/s ---- rate1/rate2=k(A1)n/k(A2)n k canceled (.1M/s)/(.4M/s)=(4M/1M)n 1/4=4n n=-1 but the reaction rate is usually proportional to the concentration of the reactant, which means reactants with a higher concentration have a greater reaction rate, in a few case, increase the concentration of reactant have little effect for the reaction rate. So, the order of the reaction is usually positive in a few case, it's close to 0. For more information about the relationship between reaction rate and the concentration of recants check out: http:/en.wikipedia.org/wiki/Reaction_rate http:/www.chemguide.co.uk/physical/basicrates/concentration.html
rate = k[A], k= rate constant / of proprotion , [] =concentration. (@ = change in []concentration ,@t change in time)a A +bB-> cC from this the rate = -1/a(@[A]/@t) =-1/b(@[B]/@t) =1/c(@[C]/@t where the small letters are the coefficents . so the rate of a reaction is equal to each other when ajusted by the coeffiects . note that the reactants are negative becasue it is decreasing as products form..the basic difference of a fist order and a second is proportions.. fist is directly proportional id est concentration goes up by 2 the rate goes up by two.while second is proportional to the square.concentration goes up by two the rate goes up by 41. First-Order ReactionsA first order reaction (order = 1) has a rate proportional to the concentration of one of the reactants. A common example of a first-order reaction is the phenomenon of radioactive decay. The rate law is:rate = k[A] (or B instead of A), with k having the units of sec-12. Second-Order ReactionsA second-order reaction (order = 2) has a rate proportional to the concentration of the square of a single reactant or the product of the concentration of two reactants:rate = k[A]2 (or substitute B for A or k multiplied by the concentration of A times the concentration of B), with the units of the rate constant M-1sec-1
Since the reaction is first order with respect to H2, if the concentration of H2 were halved, the rate of the reaction would be halved. This can be seen by entering one for each value in the rate equation, then changing the value of [H2] to 1/2 while keeping the other values the same: The rate changes from 1 to 1/2.
In a zero order overall process, the rate and rate constant will be the same. (Reaction order is an exponent, and if that exponent is "0" then the value is "1" and will cancel out.)
0.4 (mol/L)/s
No, 0.01 is not written as 0.01% in percent rate. 0.01 in percent rate is 1%.
Chain Reaction - 1980 1980-04-01 was released on: USA: 1 April 1980
Chain Reaction - 1980 1980-05-01 was released on: USA: 1 May 1980
A + B --> C has non-elementary reaction rate equation -rA = kCACB1/2 The exponent of CA is 1, the exponent of CB is 1/2, for an overall reaction order of 1 + (1/2) = 1.5. Do not let the stoichiometric coefficients from the reaction mislead you. It has to do with the rate equation for a given reaction, not the (net) chemical reaction itself.
1. The rate of forward reaction = to the rate of backward reaction. 2. Concentration of the substance are constant.
The overall reaction order for k[A]^2[B][C] would be 4 Because [A] has a rate order of 2 [B] has a rate order of 1 [C] has a rate order of 1 And when you add them together... 2 + 1 + 1 You obtain four
the answer is rate
temperature is proportional to 1/time taken for reaction to complete (rate of reaction)
equilibrium means the rate of forward reaction = rate of backward reaction... there are three types of equilibrium 1. amount of products > amount of reactants 2. amount of products = amount of reactants 3. amount of products < amount of reactants