Iron(III) hydroxide is obtained.
FeCl3 + 3NaOH = Fe(OH)3 + 3NaCl
A. Fe^2+ ==> Fe^3+ + e- is an oxidation reactionB. Fe^3+ +e- ==> Fe^2+ is a reduction reactionC. Fe(s) ==> Fe(l) is neither an oxidation nor a reduction reaction. It is a phase change.D. Fe + 2e- ==> Fe^2+ is not a possible reaction.
Hg will have 80 electrons.
FeBr2 + H3PO4 <--> Fe3(PO4)2 + HBr
FeSO4 + K3PO4 ---> Fe3(PO4)2 + K2SO4
ferrous ions and Fe3+ is ferric ion
Fe3+ + 3OH- _____> Fe(OH)3
A. Fe^2+ ==> Fe^3+ + e- is an oxidation reactionB. Fe^3+ +e- ==> Fe^2+ is a reduction reactionC. Fe(s) ==> Fe(l) is neither an oxidation nor a reduction reaction. It is a phase change.D. Fe + 2e- ==> Fe^2+ is not a possible reaction.
FeCl3
3FeCl2+2Na3PO4=Fe3(PO4)2+6NaCl
Fe3+ + SCN1- ---> FeSCN2+
b. Fe3 plus ions
When 90.0mL of 0.10M Fe3 plus 3 is added to 10.0 mL of SCN minus 1, you get an equilibrium molar concentration of FeNCS plus 2. This is determined from a calibration curve of 1.0x10-6 mol/L.
Hg will have 80 electrons.
FeBr2 + H3PO4 <--> Fe3(PO4)2 + HBr
FeSO4 + K3PO4 ---> Fe3(PO4)2 + K2SO4
ferrous ions and Fe3+ is ferric ion
Cu is being reduced and Zn is being oxidized, hence Zn + CuSO4 --> ZnSO4 + Cu