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When potassium iodide reacts with lead nitrate, a double displacement reaction occurs. The potassium ion and the lead ion switch places to form potassium nitrate and lead iodide. This reaction results in the formation of a yellow precipitate of lead iodide.
AgNO3(aq) + KI(aq) = KNO3(aq) + AgI(s) This is a classic test for halogens, and AgI precipitates down as a yellow solid.
A yellow precipitate of lead iodide forms, while potassium nitrate remains in solution. This reaction is a double displacement reaction with an exchange of ions between the two compounds.
When silver nitrate reacts with potassium iodide, a precipitation reaction occurs where silver iodide is formed. The balanced chemical equation for this reaction is: AgNO3 + KI -> AgI + KNO3. The silver iodide formed will appear as a yellow solid precipitate.
The compound precipitate formed when potassium iodide is added to a solution of lead nitrate is lead iodide, which is a yellow precipitate. This reaction is a double displacement reaction where the potassium ion and nitrate ion switch partners to form potassium nitrate and lead iodide.
A yellow precipitate of lead iodide is formed due to the reaction between potassium iodide and lead nitrate. This reaction is a double displacement reaction, where the potassium from potassium iodide swaps places with the lead from lead nitrate, forming the insoluble lead iodide.
When potassium iodide reacts with lead nitrate, a double displacement reaction occurs. The potassium ion and the lead ion switch places to form potassium nitrate and lead iodide. This reaction results in the formation of a yellow precipitate of lead iodide.
A white precipitate of silver iodide forms due to the reaction between silver ions and iodide ions, leaving potassium nitrate in solution. This reaction is a double displacement reaction and is used as a test for iodide ions.
The solid formed when adding lead nitrate and potassium iodide and filtering the mixture is lead iodide. Lead iodide is a yellow precipitate that forms by the reaction between lead nitrate and potassium iodide.
The chemical equation for the reaction between lead nitrate (Pb(NO3)2) and potassium iodide (KI) to form lead iodide (PbI2) and potassium nitrate (KNO3) is: Pb(NO3)2 + 2KI → 2KNO3 + PbI2
AgNO3(aq) + KI(aq) = KNO3(aq) + AgI(s) This is a classic test for halogens, and AgI precipitates down as a yellow solid.
A yellow precipitate of lead iodide forms, while potassium nitrate remains in solution. This reaction is a double displacement reaction with an exchange of ions between the two compounds.
When silver nitrate reacts with potassium iodide, a precipitation reaction occurs where silver iodide is formed. The balanced chemical equation for this reaction is: AgNO3 + KI -> AgI + KNO3. The silver iodide formed will appear as a yellow solid precipitate.
In the reaction: Lead (Ⅱ) Nitrate + Potassium Iodide → Potassium Nitrate + Lead (Ⅱ) Iodide.. all nitrates are soluble and lead(ii)iodide is insoluble.
The compound precipitate formed when potassium iodide is added to a solution of lead nitrate is lead iodide, which is a yellow precipitate. This reaction is a double displacement reaction where the potassium ion and nitrate ion switch partners to form potassium nitrate and lead iodide.
When solutions of lead nitrate and potassium iodide are mixed, a yellow precipitate of lead iodide is formed. This reaction is a double displacement reaction where the lead from lead nitrate reacts with the iodide from potassium iodide to form the insoluble lead iodide.
When sodium nitrate (NaNO3) reacts with potassium iodide (KI), it forms sodium iodide (NaI) and potassium nitrate (KNO3). This reaction is a double replacement reaction, where the positive ions from each compound switch places. The chemical equation for this reaction is: NaNO3 + KI → NaI + KNO3.