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Thio: 1 mole S2O32- = 2 equivalent So Eq. mass = 0.5 * (molar mass)
· In analytical chemistry, sodium thiosulphate is used for the determination of the strength of a given solution of iodine. · Sodium thiosulphate is preferred in iodometric analysis due to the fact that sodium thiosulphate is oxidized by iodine. It is also used to determine the strength of many oxidizing agents.
sodium thiosulphate
Titrate each solution separately with solution of known concentration of sodium thiosulphate. The titre value will give the amount of thiosulphate reacted with iodine, hence you can find concentration of iodine.
Dissolution.
In iodometry sodium thiosulphate is used because it is standardized by potassium dichromate and it is the best and relaible way to standardized sodium thiosulphate using iodometric titration. Infact sodium thiosulphate is also standardized by iodimetry. The difference between both of them is only of iodine. In iodometry iodine gas is liberated that will further react with sodium thiosulphate but in iodimetry standard solution of iodine is used.
Thio: 1 mole S2O32- = 2 equivalent So Eq. mass = 0.5 * (molar mass)
· In analytical chemistry, sodium thiosulphate is used for the determination of the strength of a given solution of iodine. · Sodium thiosulphate is preferred in iodometric analysis due to the fact that sodium thiosulphate is oxidized by iodine. It is also used to determine the strength of many oxidizing agents.
sodium thiosulphate
because sodium thiosulphate is unstable and iodine also so to maintain neutral medium we have to use sodiumcarboate
This reaction may be misunderstood as a direct reaction between the thiosulphate and iodate ions , however, in practice an iodide and acid mediated production of iodine from the iodate is used to react with the thiosulphate. A standard reaction used to calibrate a solution of sodium thiosulphate is as follows: Acid and potassium iodide are added to a solution of potassium iodate getting the following reaction: KIO3 + 5KI + 3H2SO4 = 3I2 + 3K2SO4 + 3H2O represented by the following ionic equation: IO3- + 5I- + 6H+ = 3I2 + 3H2O Thiosulpathe is titrated against this solution (effectively against iodine): I2 + 2Na2S2O3 = Na2S4O6 + 2NaI represented by the following ionic equation: I2 + 2S2O32- = S4O62- + 2I- where the dark brown coloured solution of iodine turns pale yellow and finally colourless as the reaction proceeds (starch is used as indicator after the pale yellow transition forming a black solution due to an iodine-starch complex which turns colourless upon further addition of thiosulphate).
Titrate each solution separately with solution of known concentration of sodium thiosulphate. The titre value will give the amount of thiosulphate reacted with iodine, hence you can find concentration of iodine.
Dissolution.
The polyatomic anions in sodium sulphate have the formula SO4-2, while the polyatomic anions in sodium thiosulphate have the formula S2O3-2.
Any reaction occur between NaCl and and I2.
reaction takes place faster than of a solution that is less concentrated
Well, if your talking about the reaction between sodium bromide (NaBr) and Iodine, then I don't think that it will replace bromine. Bromine is higher on the reactivity series, so if they come into contact with each other, there won't simply be any reaction