I believe the answer is C12H22O11 + 12O2 = 12CO2=11H2O
it adds up but not sure if the products are correct
This is a combustion reaction for the alkane ethane:
C2H6 + 3.5O2 ----------> 2CO2 + 3H2O
2C2H6+7O2-------------> 4CO2 + 6H2O
This is a combusion.So CO2+H2O formed. 2C10H22+31O2--->20CO2+22H2O
H2O and CO2
Cu (copper) reacts with CO2 (carbon dioxide), H2O (water), and O2 (oxygen) to form a product. The specific product formed depends on the reaction conditions and stoichiometry. Without further information, it is not possible to determine the exact reaction and product formed.
The product is water:2 H2 + O2 = 2 H2O
One possible product of each is gvien below: 1. Ca + SO3 = CaSO3 2. SbCl3 + Cl2 = SbCl5 3. N2 + 3 H2 = 2 NH3 4. S + O2 = SO2
Hydrated Iron (III) oxide: 2Fe + 1.5O2 + xH2O -> Fe2O3·xH2O where x is the number of H2O molecules present.
2Cu + O2 ==> 2CuO product is copper(II) oxide4Cu + O2 ==> 2Cu2O product is copper(I) oxide
n+o2=no2
2c12h22o11 + 35o2 -> 24co2 + 22h2o site is acting up again. all letters are capitalized
Hydrogen peroxide.
The product is nitrogen dioxide.
816 g C12H22O11 x (1 mol C12H22O11 / 342.0 g C12H22O11) x (12 mol O2 / 1 mol C12H22011) x (22.4 L O2 / 1 mol O2) = 641 L O2
Cu (copper) reacts with CO2 (carbon dioxide), H2O (water), and O2 (oxygen) to form a product. The specific product formed depends on the reaction conditions and stoichiometry. Without further information, it is not possible to determine the exact reaction and product formed.
The product is water:2 H2 + O2 = 2 H2O
c24h44o22+2h2o
That would be combustion with the products being carbon dioxide and water (assuming complete combustion) and a release of energy.
4Na + O2 = 2Na2O The reactants are the sodium (Na) and the oxygen (O2) NB The product is Na2O
One possible product of each is gvien below: 1. Ca + SO3 = CaSO3 2. SbCl3 + Cl2 = SbCl5 3. N2 + 3 H2 = 2 NH3 4. S + O2 = SO2
Hydrated Iron (III) oxide: 2Fe + 1.5O2 + xH2O -> Fe2O3·xH2O where x is the number of H2O molecules present.