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The total resistance of a circuit is the sum of the supply's internal resistance and its load resistance, because they are in series with each other. This is true regardless of the magnitude of, or the variation in, the current.
This is because the resistance is measured by applying a fixed voltage to the resistor and measuring the current. Since I = V/R, the current/resistance relation is non-linear.
how do you use ohms law express conductance in terms of current and voltage?
When the value of the load resistance in a transformer is changed, it will affect the current flowing through the circuit. Increasing the load resistance will decrease the current, while decreasing the load resistance will increase the current. This change in current will in turn affect the voltage across the load and the efficiency of the transformer.
Ohm's law gives the relationship between current, voltage, and resistance. The law states that I=V/R, where I is current, V is voltage, and R is resistance. Source: university digital fundamentals
Ohm's Law: voltage = current * resistance. If resistance is a constant, then voltage is directly proportional to current.
ohm
The total resistance of a circuit is the sum of the supply's internal resistance and its load resistance, because they are in series with each other. This is true regardless of the magnitude of, or the variation in, the current.
This is because the resistance is measured by applying a fixed voltage to the resistor and measuring the current. Since I = V/R, the current/resistance relation is non-linear.
voltage depend on current and resistance r.p.m depend on no of pole
The relation is:P = I2RWhere:I is the current (for example, in amperes)R is the resistance (for example, in ohms)P is the power (energy per second) converted from electrical energy to heat. If the current is in amperes and the resistance in ohms, then power is in watts (equal to joules/second).
how do you use ohms law express conductance in terms of current and voltage?
The ratio of current flow through individual branches of a parallel circuit is inversely proportional to the ratio of resistance of each branch.
When the value of the load resistance in a transformer is changed, it will affect the current flowing through the circuit. Increasing the load resistance will decrease the current, while decreasing the load resistance will increase the current. This change in current will in turn affect the voltage across the load and the efficiency of the transformer.
Voltage = (current) x (resistance) Current = (voltage)/(resistance) Resistance = (voltage)/(current)
Voltage = (current) x (resistance) Current = (voltage)/(resistance) Resistance = (voltage)/(current)
Yes, the efficiency increases. Yes, it is linear. Power lost in a current-carrying conductor is: P = I^2 * R So, if you halve the resistance, you halve the power loss. Note though that the current (I) term is squared. So if you can decrease the current by increasing the transmission voltage, the increase in efficiency is not linear, but exponential! Halve the current (and double the voltage to get the same power), and you reduce losses by four times! This is why utilities use such high voltages for transmission. Superconductors are no different, you are still talking about a reduction in resistance, superconductors just achieve a much lower resistance than a standard conductor. The question is whether the cost of superconductors and their cooling systems (currently very high) outweigh the modest gain in transmission efficiency.