The relationship is expressed by Ohm's Law: V=IR (voltage = current times resistance).
If you don't change the voltage between the ends of the circuit,then higher resistance in the circuit means lower current (amps).
The formula is Resistance= Voltage/ Amps(current) In your example: R=50/2.5, so the answer is 20 ohms.
You don't have enough information in your question, you need to include the voltage as well. One relevant equation is V = I * R where V: Voltage, I: Amps, and R: Resistance. When you have the voltage divide the Ohm resistance into that and you'll get your amps.
Amps are units of current, watts are units of power. Watts are the product of Amps times Volts. Watts = Amps x Volts.
3.0 or threeAnswerIt depends how they are connected.In series, ther total resistance will be 220 ohms and, so, the current will be 120/220 = 0.545 A.In parallel, ther total resistance will be 20 ohms and, so, the current will be 120/20 = 6 A.
Current is inversely proportional to resistance. If you double the resistance, you halve the current. Ohm's Law: Volts = Amps * Ohms Solve for Amps: Amps = Volts / Ohms
If you don't change the voltage between the ends of the circuit,then higher resistance in the circuit means lower current (amps).
The relationship between Volts, Amps and resistance is expressed by the following formulas. V = A*R, A = V/R, R = V/A, So to calculate the resistance of the lightbulb use R=220/10. Resistance equals 22 ohms. If you were to measure the resistance of the bulb with an ohm-meter you would get a lower reading. The resistance of the filement goes up as the bulb heats up. So the current (amps) are higher than 10 amps when the bulb is first turned on.
power in watts = voltage in volts x current in amps. or power in watts = current in amps x (resistance in ohms) squared i think what you meant was power in watts =(current in amps)squared x resistance in ohms
The "current" through any conductor is voltage across the conductor/conductor's resistance .The current is measured in "Amperes" (amps)."MA" stands for "Milliamps". There are 1,000 of those in one whole ampere.So, the current through a conductor is1,000 times the voltage across the conductor/conductor's resistance . . . in MA
40 A -providing the voltage remains constant.
Amps measure current; watts measure power; there is no way to convert between them without knowing more, such as either the voltage or the resistance.
Ohms Law is used for the measurement of resistance. You can find the resistance in a series circuit using this equation; amps=volts/resistance or volts=amps x resistance.The Power Law is used to find the wattage in the circuit. You can find the amount of watts using this equation: watts=volts x amps.CommentOhm's Law has nothing whatsoever to do with either resistance or power.The equation, R = E/I, is derived from the definition of the ohm, and not from Ohm's Law.Ohm's Law simply describes a linear relationship between the potential difference across a conductor and the current through it. It does NOT describe the relationship between potential difference, current, and resistance.
Ohms law is: I = V / R (current = voltage / resistance)... where if the voltage or resistance changes then the current will change. ... the current and resistance is a inversely proportional linearly relationship ...this means that if the resistance doubles then the current halfs, if the resistance halfs then the current doubles, etc...hope this helps
Resistance (Ohms) = Potential Difference (Voltage) / Current (Amps)
ohms is a measure of resistance(R) in a circuit. Watts is a measure of the power(P), in this case lets assume it is the power used by the resistive element (lamp, heater etc). Power(watts)=Current(Amps)x Current(amps) x Resistance(ohms) or Resistance (ohms)=Power(W)/(current x current)
Resistance is the opposition to the flow of electric current through a conductor. It is defined as the ratio of the potential difference (volts) between the ends of the conductor to the magnitude of the current (amps) through the conductor.