The RMS (root mean square) of the peak voltage of a sine wave is about 0.707 times the peak voltage. Recall that the sine wave represents a changing voltage, and it varies from zero to some positive peak, back to zero, and then down to some negative peak to complete the waveform. The root mean square (RMS) is the so-called "DC equivalent voltage" of the sine wave. The voltage of a sine wave varies as described, while the voltage of a DC source can be held at a constant. The "constant voltage" here, the DC equivalent, is the DC voltage that would have to be applied to a purely resistive load (like the heating element in a toaster, iron or a clothes dryer) to get the same effective heating as the AC voltage (the sine wave). Here's the equation: VoltsRMS = VoltsPeak x 0.707 The 0.707 is half the square root of 2. It's actually about 0.70710678 or so.
rms is root means square (average of the sine wave) and peak value is the top of the sine wave
ANSWERis root means square and it is not AVERAGE the average is .639 of RMS AND PEAK VOLTAGE IS 1.41 X rms. Find it in any book
CommentThe average value of a complete sine wave is zero. The figure of 0.639 Vmax or 0.639 Imax is the average over half its wavelength.
The rms-value of a sine wave is 0.707Vmax or 0.707Imax.
Peak to peak voltage is the voltage differential between highest and lowest voltages in a waveform. In a typical AC (sinusoidal) waveform of 117 volts, the peak to peak voltage would be about 165 volts.
RMS voltage is the average value, specifically the Root Mean Squared voltage. RMS voltage for a sinusoidal waveform is peak to peak voltage divided by the square root of two.
The conversions for other wavforms, such as triangle, are different. In essence, the RMS voltage is the square root of the limit of the sum of the squares of the voltages divided by N, where N approaches infinity. Root of the Mean of the Square. In the extreme case of a square wave, RMS voltage and peak to peak voltage are the same.
The RMS value is used because it more correctly describes the available average power in a varying voltage or current source. When stating an AC voltage, RMS is implied, unless some other method is stated, i.e. 120VAC means 120VAC-RMS.
If the sine wave is symetrical about zero volts then peak is one half peak to peak voltage.
Peak to peak voltage = 2 * (peak voltage)
the answer is 5.6vp-p
12.68V 3o * sin25 = 12.67854785
Vpp is Peak-to-Peak voltage, in other words, in AC voltage, the peak-to-peak voltage is the potential difference between the lowest trough in the AC signal to the highest. Assuming the reference to the voltage is zero, Vpp would be twice the peak voltage (between zero and either the highest or lowest point in the AC waveform). Vrms is the Root Mean Square voltage, think of it as sort of an average (it's not quite that simple). For a sine wave, the RMS voltage can be calculated by y=a*sin(2ft) where f is the frequency of the signal, t is time, and a is the amplitude or peak value.
if that 144 is the peak voltage if its a sine wave the rms voltage is that voltage divided by sqrt(2) if not a sine wave (modified) you must find the area under the curve by integrating a cycle of that wave shape (root mean squared)
For a sine wave, the form factor is the square root of 2. Thus, the effective voltage of 56 V (56 Vrms) is 2-1/2 times the peak-to-peak voltage. Thus, the peak-to-peak voltage Vpp = Vrms * sqrt(2)In this example:Vpp = 56V * 1.4142... = 79.2V (rounded to one decimal place)
No, the peak-to-peak voltage is 2sqrt(2) times as much as the rms for a pure sine-wave.
the answer is 5.6vp-p
Assuming sine wave (it is different if not): Vp-p = 2.828 * Vrms
To calculate the peak voltage of an RMS voltage in a sine wave simply multiply the RMS voltage with the square root of 2 (aprox. 1,414) like this: 240 x 1,414 = 339,4 V RMS x sqr.root of 2 = peak voltage
4volts x 2.8 =9.6 v
Peak voltage will be 1.414 times the RMS. Peak to Peak voltage, assuming no DC offset, will be 2 x 1.414 x the RMS value.
12.68V 3o * sin25 = 12.67854785
Vpp is Peak-to-Peak voltage, in other words, in AC voltage, the peak-to-peak voltage is the potential difference between the lowest trough in the AC signal to the highest. Assuming the reference to the voltage is zero, Vpp would be twice the peak voltage (between zero and either the highest or lowest point in the AC waveform). Vrms is the Root Mean Square voltage, think of it as sort of an average (it's not quite that simple). For a sine wave, the RMS voltage can be calculated by y=a*sin(2ft) where f is the frequency of the signal, t is time, and a is the amplitude or peak value.
RMS stands for "Root of the Means Squared", and is a mathematical method of defining the "operating" voltage of a sine wave power source. Typical home lighting and outlet voltage presently is 120 VAC (volts alternating current), 60 Hz. (Hertz, formerly referred to as "cycles per second".) But the PEAK voltage is the absolute maximum voltage at the "peak" of each sine wave of voltage. Mathematically, the "Peak" voltage is 1.414 (which is the square root of the number 2) times the RMS voltage, and conversely, the RMS voltage is 0.707 times the PEAK voltage.
if that 144 is the peak voltage if its a sine wave the rms voltage is that voltage divided by sqrt(2) if not a sine wave (modified) you must find the area under the curve by integrating a cycle of that wave shape (root mean squared)
For a sine wave, the form factor is the square root of 2. Thus, the effective voltage of 56 V (56 Vrms) is 2-1/2 times the peak-to-peak voltage. Thus, the peak-to-peak voltage Vpp = Vrms * sqrt(2)In this example:Vpp = 56V * 1.4142... = 79.2V (rounded to one decimal place)
The rms of 10V is 6.02V. Take the peak voltage of the sine wave and multiply it by 0.707.