The assumption of the previous answer is wrong. By passing them through the correct medium, the velocity at which protons travel can be reduced. This follows the theory of relativity, which only sets a maximum value for light speed, not a minimum. The equations:
E=hv
[E-energy [J] | h-Planck's constant [6.6260755 x 10¯34 Joule second] | v-frequency [Hz, sec-1]]
and
λν=c
[λ-wavelength [m] | ν-frequency [Hz, sec-1] | c-speed of light (photon) [m/s]]
still hold true however. You can re-arrange the second equation such that λ=c/v . From this equation you can see that the relationship of wavelength and photon velocity are directly proportional. That is to say as the wavelength increases, so too does it's velocity - so long as the frequency of the sinusoidal wave stays constant.
inversely related
The energy per photon is directly proportional to the frequency; the frequency is inversely proportional to the wavelength (since frequency x wavelength = speed of light, which is constant); thus, the energy per photon is inversely proportional to the wavelength.
The de Broglie wavelength of a proton becomes shorter.
After the absorption, the matter has added energy equal to 'hf' the energy of the absorbed photon.
The shorter the wavelength of a wave, the higher its energy.
The relationship between electromagnetic energy (photon energy) and wavelength is determined by two constants - the speed of light and Planck's constant. Photon energy (in Joules) is equal to the speed of light (in metres per second) multiplied by Plancks constant (in Joule-seconds) divided by the wavelength (in metres). E = hc/wavelength where: E is photon energy h is Planck's constant = 6.626 x 10-34 Js c is the speed of light = 2.998 x 108 m/s This relationship shows that short wavelengths (e.g. X-rays) have high photon energies while long wavelengths (e.g. Radio waves) have low photon energies.
You need to know the photon's frequency or wavelength. If you know the wavelength, divide the speed of light by the photon's wavelength to find the frequency. Once you have the photon's frequency, multiply that by Planck's Konstant. The product is the photon's energy.
The wavelength of the detected signal.
When a photon goes say from air to water, it slows down according to; n=c/v where n is refractive index of water c is velocity of light in air v is velocity of light in water It is stated that the frequency of the photon doesn't change when the photon enters the water. Only the wavelength changes.
Wavelength is a measure of depth/distance - namely the distance between peaks or troughs in a wave. For light this is referring to peaks/troughs of signal strength. Because the front velocity of a photon of light is always constant (ALWAYS, WITH RESPECT TO ALL FRAMES OF REFERENCE IN THE UNIVERSE, NO EXCEPTIONS), the wavelength of a photon is also a direct measure of it's energy.
Depends on the wave. In electromagnetic waves, a shorter wavelength means a higher frequency - and the energy of a photon is directly proportional to frequency.
Generally if they are of the same wavelength, then the atom will absorb the photon at that wavelength.