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What is the relationship between the horizontal and vertical components of velocity for a projectile launched at an angle between 0 and deg and 90 and deg?
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Example problem and answer of projectile motion?
-- In what direction should a projectile be launched in order to achieve the maximum range ? -- Toward 45 degrees above the horizontal.
Is it true that a projectile launched into space at any angle will have a constant horizontal velocity?
If space were entirely empty this would be true, but even minute gravitational forces can change the trajectory and velocity of a projectile.
Is an object sliding along a horizontal table an example of projectile motion?
No. The definition of projectile motion is an object dropped launched into the air, which is acted upon by gravity. (For the basic forms of the motion, air resistance is ignored.)
What do you need to know to determine how far a projectile travels horizontally?
initial velocity, angle of launch, height above ground When a projectile is launched you can calculate how far it travels horizontally if you know the height above ground it was launched from, initial velocity and the angle it was launched at. 1) Determine how long it will be in the air based on how far it has to fall (this is why you need the height above ground). 2) Use your initial velocity to determine the horizontal component of velocity 3) distance travelled horizontally = time in air (part 1) x horizontal velocity (part 2)
What is the vertical acceleration of a projectile caused by?
Here on Earth, the vertical acceleration of any projectile is -9.81ms-2. The minus sign shows that they accelerate downwards. This is true for an object dropped from a height, however the question refers to a projectile, which implies an object that has been launched by a mechanism. It thus has both a horizontal and a changing vertical acceleration in addition to the constant downward gravitational acceleration. A general solution can be found in the related link. (Or by studying the pages in your textbook assigned by your teacher.)
Example problem and answer of projectile motion?
-- In what direction should a projectile be launched in order to achieve the maximum range ? -- Toward 45 degrees above the horizontal.
Which projectile would hit the ground faster one projected at 20 meters per second horizontally or one projected at 20 meters per second in a direction other than horizontal no air?
If the non-horizontal projectile is launched abovehorizontal, thenit's the second one to hit the ground, after the horizontal one.If the non-horizontal one is launched below horizontal, then it'sthe first to hit the ground, before the horizontal one.
Under what conditions will a projectile travel maximum range?
Ignoring the effects of wind and air-resistance in general, maximum projectile range results when the projectile is launched/fired in a direction 45 degrees above the horizontal.
What is the angle for maxium altitude?
A baseball, cannonball, or other projectile launched at a 45° angle above the horizon will achieve maximum horizontal range. A projectile launched straight up will achieve maximum altitude, but you kind of have to watch it and be careful when it returns.
Is it true that a projectile launched into space at any angle will have a constant horizontal velocity?
If space were entirely empty this would be true, but even minute gravitational forces can change the trajectory and velocity of a projectile.
Is an object sliding along a horizontal table an example of projectile motion?
No. The definition of projectile motion is an object dropped launched into the air, which is acted upon by gravity. (For the basic forms of the motion, air resistance is ignored.)
Is projectile launched into space an example of centrifugal force?
A launched projectile is not an example of centrifugal force. It is an example of centripetal force.
When is projectile considered a free fall?
As soon as it is launched, a projectile is in free fall.
Why projectile angle increase when projectile range also increase?
Range of a projectileThe path of this projectile launched from a height y0 has a range d.In physics, a projectile launched with specific initial conditions in a uniform gravity field will have a predictable range. As in Trajectory of a projectile, we will use:g: the gravitational acceleration-usually taken to be 9.80 m/s2 (32 f/s2) near the Earth's surfaceθ: the angle at which the projectile is launchedv: the velocity at which the projectile is launchedy0: the initial height of the projectiled: the total horizontal distance travelled by the projectileWhen neglecting air resistance, the range of a projectile will beIf (y0) is taken to be zero, meaning the object is being launched on flat ground, the range of the projectile will then simplify toso to increase the range θ shoud vary from 0 to 45 and after 45 it starts decreasing.
What is the largest angle a projectile can be launched?
180 Degree
What do you you need to know to determine how far a projectile travels horizontally?
initial velocity, angle of launch, height above ground When a projectile is launched you can calculate how far it travels horizontally if you know the height above ground it was launched from, initial velocity and the angle it was launched at. 1) Determine how long it will be in the air based on how far it has to fall (this is why you need the height above ground). 2) Use your initial velocity to determine the horizontal component of velocity 3) distance travelled horizontally = time in air (part 1) x horizontal velocity (part 2)
What do you need to know to determine how far a projectile travels horizontally?
initial velocity, angle of launch, height above ground When a projectile is launched you can calculate how far it travels horizontally if you know the height above ground it was launched from, initial velocity and the angle it was launched at. 1) Determine how long it will be in the air based on how far it has to fall (this is why you need the height above ground). 2) Use your initial velocity to determine the horizontal component of velocity 3) distance travelled horizontally = time in air (part 1) x horizontal velocity (part 2)
