That depends on what voltage it's designed to operate from.
Power = (voltage)2 / R
R = Voltage2 / power
If it's a 117-volt bulb, R = (117)2 / 28 = 489 ohms.
If it's a 240-volt bulb, R = (240)2 / 28 = 2,057 ohms.
On this calculation I am assuming that the light bulb is using a 120 volt source. Watts = Amps x Volts. Amps = Watts/Volts, 40/120 = .33 amps. R = Volts/Amps, 120/.33 = 363.6 ohms resistance in the 40 watt light bulb.
It is probably a 60 watt bulb (believe it or not). Bulbs are rated in watts. A 100 watt bulb is brighter and consumes more power than a 60 watt bulb
A 60 watt light bulb is a light bulb with 60 watts capacity. When talking about watts, you're talking about the power that is transferred from the appliance to the accessories. Therefore, the light bulb labeled "60 watts" takes 60 watts to light up. A 60 watt light bulb will not be as bright as a 120 watt light bulb.
A low resistance bulb has a thicker filament.
no
No, the highest wattage bulb will have the lowest resistance.
The resistance of a light bulb varies, depending on the type of bulb, the power rating, and the temperature. A typical incandescent 60 watt bulb, for instance has a cold resistance of about 30 ohms, and a hot resistance of about 240 ohms.
It means exactly what it sounds like. The resistance of an incandescent bulb's filament depends on its temperature. A filament has a positive temperature coefficient, which means that its resistance increases as its temperature increases. A typical 40 watt bulb (120 volts) has a cold resistance of about 28 ohms, but its hot, operating resistance is about 360 ohms. If the cold resistance were constant, the bulb would dissipate 379 watts. In fact, cold turn on is the most stressful time for a bulb.
As per the formula for power (Power (Watt) = Voltage (V) x Current (i) & Resistance (R) = V / i), 25w lamp bulb would have higher resistance compared to that of 5w lamp bulb.
On this calculation I am assuming that the light bulb is using a 120 volt source. Watts = Amps x Volts. Amps = Watts/Volts, 40/120 = .33 amps. R = Volts/Amps, 120/.33 = 363.6 ohms resistance in the 40 watt light bulb.
Yes. A 60W bulb has a higher resistance than the 40W buld. The extra resistance requires more current to light up the bulb. The fillament then glows brighter.
No. A 70 Watt metal halide bulb can not be replaced with a 150 Watt halide bulb.
The resistance of the bulbs doesn't depend on the voltage source. They can be wrapped in tissue in cardboard boxes in the drawer. If one bulb is designed to dissipate 200 watts and another is designed to dissipate 600 watts when they're both energized by the same voltage, whatever that is, then the 200-watt bulb has three times the resistance of the 600-watter.
A 100 watt 220 volt light bulb (or anything consuming 100 watts on 220 volts) draws 100/220, or .45 Amps. It will also have about 220²/100, or 484 ohms resistance. A 60 watt 220 volt light bulb (or anything consuming 60 watts on 220 volts) draws 60/220, or .27 Amps. It will also have about 220²/60, or 807 ohms resistance.
The resistance is equal to the voltage-squared divided by the power. So a 1kW heater is 52.9 ohms, a 100 watt bulb is 529 ohms. The basic formula is W = V^2 / R
Yes.
A watt is a measurement of electricity, usually pertaining to light. Light bulbs luminosity is graded by wattage, such as a 60 watt bulb, 100 watt bulb and so on. You would find a watt in a light bulb, to start.