When sodium chloride and silver nitrate are mixed, a metathesis reaction takes place. The silver ion becomes bonded to the chloride ion. Since silver chloride is insoluble, this substance precipitates out of solution.
The silver nitrate reacts with the chloride ion from NaCl and a white milky precipitate of Silver Chloride is formed. This turns brown/purple/black on exposure to light.
AgNO3 + NaCl --> NaNO3(aq) + AgCl(s)
AgCl will form a white precipitate, where as NaNO3 is soluble in water.
The reaction is:
NaCl + AgNO3 = NaNO3 + AgCl(s)
Silver chloride is a white precipitate.
The reaction is:
AgNO3 + NaCl = NaNO3 + AgCl(s)
Silver chloride is an insoluble white precipitate.
The reaction is:
NaCl + AgNO3 = NaNO3 + AgCl(s)
The reaction is:
AgNO3 + NaCl = AgCl + NaNO3
Silver chloride is a white insoluble precipitate.
The reaction is:
NaCl + AgNO3 = AgCl(s) + NaNO3
AgCl(s) + NaNO3 (aq)
compound
AgNO3(aq) + NaCl(aq) --> AgCl(s) + NaNO3(aq)
The reaction is: NaCl + AgNO3 = NaNO3 + AgCl Silver chloride is a white precipitate.
(C) AgNO3 + NaCl --> AgCl + NaNO3
These compounds react forming a white insoluble precipitate - silver chloride: NaCl + AgNO3 = AgCl + NaNO3
Balanced equation first! AgNO3 + NaCl -> AgCl + NaNO3 all one to one, get moles AgNO3 3.82 moles NaCl (1 mole AgNO3/1 mole NaCl) = 3.82 moles AgNO3 ------------------------------- Molarity = moles of solute/Liters of solution 0.117 M AgNO3 = 3.82 moles AgNO3/Liters Liters = 3.82/0.117 = 32.6 Liters which is 32600 milliliters which is unreasonable; check answer if you can
Yes. AgNO3 + NaCl --> NaNO3 + AgCl AgCl will form a milky white precipitate, where as NaNO3 is soluble in water.
No. It must have the same number of each as reactants and products. AgNO3(aq) + NaCl(aq) -> AgCl(aq) + NaNO3(aq)
The reaction is: AgNO3 + NaCl = AgCl + NaNO3 Silver chloride is a white precipitate.
FeCl3 +KSCN + AgNO3
chemical
This depends on the amounts of these reactants.