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Assuming we neglect air resistance and start from rest in the vertical plane - use

v=u+at

so v = 0+(10x2) assuming g = 10N/kg

=20m/s

In practice it will be less because air resistance will tend to slow the skydiver down.

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12y ago
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AnswerBot

4d ago

Assuming constant acceleration due to gravity, the skydiver's downward velocity after 2 seconds can be calculated using the equation v = u + at, where v is the final velocity, u is the initial velocity (usually 0 for objects in free fall), a is the acceleration due to gravity (9.8 m/s^2), and t is the time (2 seconds). Plug the values into the equation to find the downward velocity after 2 seconds.

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Q: What is the skydiver's downward velocity after 2 seconds?
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Continue Learning about Physics

A rock is dropped from the top of a cliff what is the velocity after 2 seconds 5 seconds 10 seconds?

The velocity after 2 seconds, 5 seconds, and 10 seconds can be calculated using the formula v = gt, where g is the acceleration due to gravity (approximately 9.81 m/s^2). After 2 seconds, the velocity is 19.62 m/s downward. After 5 seconds, the velocity is 49.05 m/s downward. After 10 seconds, the velocity is 98.1 m/s downward.


What is the skydivers velocity after two seconds?

The velocity of a skydiver after two seconds would depend on factors such as air resistance, weight of the skydiver, and initial velocity. On average, a skydiver may reach a velocity of around 56 m/s (about 125 mph) after two seconds of freefall.


What is a skydivers velocity after 2 seconds?

A skydiver's velocity after 2 seconds will depend on factors such as their initial velocity, weight, air resistance, and gravitational force acting on them. On average, a skydiver will reach a terminal velocity of around 120 mph (193 km/h) after about 10 seconds of freefall.


An 8 kg mass is in free fall What is the velocity of the mass after 9 seconds?

The velocity of an object in free fall can be calculated using the equation v = gt, where g is the acceleration due to gravity (9.8 m/s^2). Plugging in the values, we get v = 9.8 m/s^2 * 9 s = 88.2 m/s. Therefore, the velocity of the 8 kg mass after 9 seconds is 88.2 m/s.


If A ball is dropped from a rooftop what is the ball's velocity after 3 seconds?

Assuming no air resistance, the velocity of the ball after 3 seconds can be calculated using the equation v = u + gt, where v is the final velocity, u is the initial velocity (0 m/s in this case), g is the acceleration due to gravity (approximately 9.8 m/s^2), and t is the time (3 seconds). Therefore, the velocity of the ball after 3 seconds would be 29.4 m/s downward.

Related questions

A rock is dropped from the top of a cliff what is the velocity after 2 seconds 5 seconds 10 seconds?

The velocity after 2 seconds, 5 seconds, and 10 seconds can be calculated using the formula v = gt, where g is the acceleration due to gravity (approximately 9.81 m/s^2). After 2 seconds, the velocity is 19.62 m/s downward. After 5 seconds, the velocity is 49.05 m/s downward. After 10 seconds, the velocity is 98.1 m/s downward.


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The velocity of a skydiver after two seconds would depend on factors such as air resistance, weight of the skydiver, and initial velocity. On average, a skydiver may reach a velocity of around 56 m/s (about 125 mph) after two seconds of freefall.


What is the speed of an object in free fall 2 seconds after falling from rest?

Acceleration of gravity near the surface of the earth is 9.8 meters (32.2 feet) per second2. Downward velocity after 2 seconds = 19.2 meters (64.4 feet) per second.


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