Assuming we neglect air resistance and start from rest in the vertical plane - use
v=u+at
so v = 0+(10x2) assuming g = 10N/kg
=20m/s
In practice it will be less because air resistance will tend to slow the skydiver down.
Assuming constant acceleration due to gravity, the skydiver's downward velocity after 2 seconds can be calculated using the equation v = u + at, where v is the final velocity, u is the initial velocity (usually 0 for objects in free fall), a is the acceleration due to gravity (9.8 m/s^2), and t is the time (2 seconds). Plug the values into the equation to find the downward velocity after 2 seconds.
The velocity after 2 seconds, 5 seconds, and 10 seconds can be calculated using the formula v = gt, where g is the acceleration due to gravity (approximately 9.81 m/s^2). After 2 seconds, the velocity is 19.62 m/s downward. After 5 seconds, the velocity is 49.05 m/s downward. After 10 seconds, the velocity is 98.1 m/s downward.
The velocity of a skydiver after two seconds would depend on factors such as air resistance, weight of the skydiver, and initial velocity. On average, a skydiver may reach a velocity of around 56 m/s (about 125 mph) after two seconds of freefall.
A skydiver's velocity after 2 seconds will depend on factors such as their initial velocity, weight, air resistance, and gravitational force acting on them. On average, a skydiver will reach a terminal velocity of around 120 mph (193 km/h) after about 10 seconds of freefall.
The velocity of an object in free fall can be calculated using the equation v = gt, where g is the acceleration due to gravity (9.8 m/s^2). Plugging in the values, we get v = 9.8 m/s^2 * 9 s = 88.2 m/s. Therefore, the velocity of the 8 kg mass after 9 seconds is 88.2 m/s.
Assuming no air resistance, the velocity of the ball after 3 seconds can be calculated using the equation v = u + gt, where v is the final velocity, u is the initial velocity (0 m/s in this case), g is the acceleration due to gravity (approximately 9.8 m/s^2), and t is the time (3 seconds). Therefore, the velocity of the ball after 3 seconds would be 29.4 m/s downward.
The velocity after 2 seconds, 5 seconds, and 10 seconds can be calculated using the formula v = gt, where g is the acceleration due to gravity (approximately 9.81 m/s^2). After 2 seconds, the velocity is 19.62 m/s downward. After 5 seconds, the velocity is 49.05 m/s downward. After 10 seconds, the velocity is 98.1 m/s downward.
The velocity of a skydiver after two seconds would depend on factors such as air resistance, weight of the skydiver, and initial velocity. On average, a skydiver may reach a velocity of around 56 m/s (about 125 mph) after two seconds of freefall.
Acceleration of gravity near the surface of the earth is 9.8 meters (32.2 feet) per second2. Downward velocity after 2 seconds = 19.2 meters (64.4 feet) per second.
A skydiver's velocity after 2 seconds will depend on factors such as their initial velocity, weight, air resistance, and gravitational force acting on them. On average, a skydiver will reach a terminal velocity of around 120 mph (193 km/h) after about 10 seconds of freefall.
The velocity of the ball 2 seconds before it reaches its highest point will be equal in magnitude but opposite in direction to the velocity it had when it was thrown upwards. This is due to the acceleration of gravity acting on the ball and gradually reducing its upward velocity until it comes to a stop at the highest point of its trajectory.
7.5
14.715 m/s. This is worked out by knowing that gravity will accelerate a body at 9.81 (m/s)/s. The average velocity is the speed at 3s plus the speed at 0s divided by 2. Speed at 0s = 0 x 9.81 = 0 m/s Speed at 3s = 3 x 9.81 = 29.43 m/s (29.43 + 0) / 2 = 14.715 m/s.
5/2 = 2.5 m/s; velocity is distance divided by time
During the 5 seconds, gravity adds 5G = (5 x 9.78) = 48.9 meters/sec to the object's downward speed.During that time, it's average downward speed is 1/2 of [ Vi + (Vi + 48.9) ] = Vi + 24.45 m/s.In 5 seconds it falls 5(Vi + 24.45) = 5Vi + 122.25 meters.5Vi + 122.25 = 240 meters5Vi = 240 - 122.25 = 117.75 metersVi = 117.75 / 5 = 23.55 meters per sec.
100
heres the average 2.2 seconds
Yes, velocity is acceleration x time. If acceleration is the same, velocity can be different as it changes with time. For example a car accelerating with constant acceleration will have a different velocity after 5 seconds than it will have at 2 seconds.