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To do this equation you use the formula: q=mc(Delta T)

Then you have to change the problem algebraically because we are trying to find 'c'.
So you have c = q
m(deltaT)

Heres your answer:
0.0573333333........
But since we have '15.0' and '47.3' then we can only have 3 significant figures.
So your final answer is:
0.057

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Wiki User

14y ago
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Wiki User

12y ago

Use this equation:

q = cmΔT

Heat(energy) = specific heat X mass x change in temperature

After looking up the specific heat of silver (units are J/ g ▪°C) you just plug and chug.

q = (0.233 J/ g ▪°C)(11.4 g)(15.5 °C)

= 41.2 J

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Wiki User

14y ago

You need to provide units. That is the most basic requirement.

is it 11.1 grammes or kilogrammes or tonnes or bushels ???? :)

Is it 14.4 deg C or F ?

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Wiki User

13y ago

c=47.3/(55x15)

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Wiki User

11y ago

35.8 J

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Anonymous

Lvl 1
3y ago

0.06

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Q: What is the heat capacity of silver metal if 55g of the metal absorbs 47.3 calories of heat and the temperature rises 15 degrees centigrade?
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