SO3 is a planar molecule with bond angles of 120 0 - the hybridisation of S is sp2
Note that a typical description of bonding involves 3 double bonds - this assumes that there is good overlap between d orbitals on the S atom and p orbitals on the O atom- calculation suggests that this pi bonding is at best very weak.
Look in a college chemistry book, or do a search online.
sp4
+6 oxidation state
SO3 is the chemical formula for sulfur trioxide.
Xe belongs to the noble gas family so has 8 valence electrons...Xe => 5s25p6....... Two of these are bonded with fluorine. Thus it is left with 6 electronss i.e. 3 lone pairs.... So hybridization is sp3d ....the shape that should be =>Trigonal bipyramidal.... But it has 3 lone pairs on equatorial plane & 2 bond pairs on axial .....so final shape =>LINEAR...
Look in a college chemistry book, or do a search online.
VSEPR notation is AX3E Tetra Pyramidal angle is 109.5 degrees sp3 hybridization VSEPR notation is AX3E Tetra Pyramidal angle is 109.5 degrees sp3 hybridization
sp4
+6 oxidation state
+4
SO3 is the chemical formula for sulfur trioxide.
Formula: SO3
Xe belongs to the noble gas family so has 8 valence electrons...Xe => 5s25p6....... Two of these are bonded with fluorine. Thus it is left with 6 electronss i.e. 3 lone pairs.... So hybridization is sp3d ....the shape that should be =>Trigonal bipyramidal.... But it has 3 lone pairs on equatorial plane & 2 bond pairs on axial .....so final shape =>LINEAR...
If you mean SO3^-2 (the sulfite anion), then S has an oxidation number of 4+, since each O atom is 2-. In sulfur trioxide, SO3, the S atom has an oxidation number of 6+.
SO3 = sulphur dioxide O2= oxygen SO3 = sulphur trioxide SO3- = sulphite that should be it .... right? :)
The oxidation state of an individual sulfur atom in (SO3)2- is 4.
Al+3 SO3+2 <---- these are the ions and their charges Al+3 Al+3 SO3+2 SO3+2 SO3+2 <---- the charges have to add up to zero, so two +3 aluminum ions cancel out three +2 sulfite ions. Al2(SO3)3 <--- simplify