0
What is the time period of a pendulum which oscillates 40 times in 4 seconds?
Wiki User
∙ 13y ago
Period of a pendulum (T) in Seconds is:
T = 2 * PI * (L/g)1/2
L = Length of Pendulum in Meters
g = Acceleration due to gravity = 9.81 m/s2
PI = 3.14
The period is independent of the mass or travel (angle) of the pendulum.
The frequency (f) of a pendulum in Hertz is the inverse of the Period.
f = 1/T
Wiki User
∙ 12y ago
Wiki User
∙ 13y agoThe swing of a pendulum is called an oscillation. The furthest point in each oscillation is the amplitude.
Wiki User
∙ 12y agoThe time of a back and forth swings is called period of a pendulum.
Wiki User
∙ 14y ago2 pi times the square root of (the length divided by acceleration due to gravity)
Wiki User
∙ 12y agoThe time period T is approximately given by:
T = 2pi sqrt(L/g)
where L is the pendulum's length, and g denotes gravitational field strength.
Wiki User
∙ 12y agoThere are 8 x 60 seconds in 8 minutes = 480 seconds, so the answer is 40 divided by 480 = 0.08333 Hertz (0.08333 cycles per second).
Wiki User
∙ 13y ago4 seconds/ 40 time = 1/10 of a second.
Add your answer:
Earn +20 pts
The gravitational acceleration on the surface of Mars is 3.7m s 2 What period Would a 64 meters long pendulum have on Mars?
The period of a pendulum on Mars compared to Earth would be about 1.62 times longer.The period of a pendulum is (among other factors) inversely proportional to the square root of the acceleration due to gravity. The gravity of Mars is 0.38 that of Earth, so the square root of one over 0.38 is 1.62.T ~= 2 pi sqrt (L/g) where theta far less than 1.For larger theta, longer periods are incurred, with various correction factors, but the basic equation remains the same.
House current in the US oscillates how many times in one second?
The general oscilattion rating for a United States household electrical system is 60 times per second. This is know as Hrtz (prnounced Hets). Therefore, home electrical systems in the US run at 60 Hrtz.
In 6 seconds a light flashes once In one hour how many times it will flash?
600, 60(seconds)x60(minutes)=3600(seconds)/6=600
How long does it take for a day to pass on Neptune?
The length of a day, or sidereal period, on Neptune is 16 hours 6 min 13 seconds (0.6713 days) Because Neptune is not a solid body, its atmosphere undergoes differential rotation. The wide equatorial zone rotates at a period of about 18 hours, at the polar regions the rotation period is about 12 hours.
You can avoid dangerous last minute maneuvers by looking ahead of your vehicle at all times?
You can avoid dangerous last minute maneuvers by looking ________ ahead of your vehicle at all times 10 to 15 seconds 20 to 25 seconds 15 to 30 Seconds
A pendulum oscillates 60 times in 6 seconds.Find its time period and frequency?
Frequency=60/6=10Hz Time Period=1/f=1/10
A pendulum that is 38 cm long will swing how many times in 15 seconds?
12.
Time period of a pendulum on moon is?
About 40.7% of that on Earth or about 2.46 times slower.
What is the difference in period for a pendulum on earth and a pendulum on moon?
The period of a simple pendulum swinging at a small angle is approximately 2*pi*Sqrt(L/g), where L is the length of the pendulum, and g is acceleration due to gravity. Since gravity on the moon is approximately 1/6 of Earth's gravity, the period of a pendulum on the moon with the same length will be approximately 2.45 times of the same pendulum on the Earth (that's square root of 6).
If the length of a simple pendulum is doubled what will be the change in its time period?
ts period will become sqrt(2) times as long.
How many times does a 32 inch pendulum swing in one minute?
Period ( left swing + right swing) of a simple pendulum = 2*pi * sqrt (L/g) in seconds. g = 32.2 feet per second2 L = 32 inches = 2.66667 feet Period = 2*pi * sqrt ( 2.66667ft/32.2) = 2*pi * 0.287777 = 1.808158 seconds for one period (two swings). Periods in one minute = 60 sec / 1.808158 sec = 33.183 periods in one minute. Times 2 = 66.366 swings in one minute.
How would the time period of a simple pendulum clock be affected if it were on the moon instead of the earth?
The time period of a pendulum would increases it the pendulum were on the moon instead of the earth. The period of a simple pendulum is equal to 2*pi*√(L/g), where g is acceleration due to gravity. As gravity decreases, g decreases. Since the value of g would be smaller on the moon, the period of the pendulum would increase. The value of g on Earth is 9.8 m/s2, whereas the value of g on the moon is 1.624 m/s2. This makes the period of a pendulum on the moon about 2.47 times longer than the period would be on Earth.
How many times the pendulum of the clock moves in 30 minutes?
That depends on the period of the clock's pendulum. If we assume it's one second, then it does 1800 cycles in half an hour.
Explain how the length of a string affects the motion of a simple pendulum?
You mean the length? We can derive an expression for the period of oscillation as T = 2pi ./(l/g) Here l is the length of the pendulum. So as length is increased by 4 times then the period would increase by 2 times.
How many times is the period of the pendulum increased or decreased when its length is increased four times?
Time period is directly proportional to the square root of the length So as we increase the length four times then period would increase by ./4 times ie 2 times.
How does the length of a string affect the number Of times a pendulum will swing back and fourth in 10 seconds?
Yes. Period proportional to (Length)-2 is the fundamental property of the pendulum. The formula for the Period (1 complete swing), T, for a pendulum of length L is: T = 2*pi sqrt (L/g) (Oh for a library of symbols to avoid computer-code abbreviations!) T is in seconds, L in metres, g, the acceleration due to gravity, = 9.8m/s2 So for a given length, it is easy to work out the number of complete swings in 1 minute.
If the length of a pendulum increases what does the period of the pendulum do?
The speed (magnitude of the velocity) of a pendulum is greatest when it is at the lowest part of it's swing, directly underneath the suspension.The factors that affect the period of a pendulum (the time it takes to swing from one side to the other and back again) are:# Gravity (the magnitude of the force(s) acting on the pendulum)# Length of the pendulum # (+ minor contributions from the friction of the suspension and air resistance)
