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Pressure, volume, temperature & the amount of gas.
That's going to depend on the substance, which the question neglects to identify. --------------------------------------------------- The volume of any gas at STP (pressure of 1 ATM & temp.: 0oC) is approximately 22.41 L/mol or 22,410 mL/mol. So you need to find out how much gas you have to begin with (# of moles) to find the volume of the gas at STP.
The scientific law that relates air pressure and volume is Boyle's law. It states that at a constant temperature, the pressure exerted by a gas is inversely proportional to its volume. In other words, as the volume of a gas decreases, its pressure increases, and vice versa.
The Ideal Gas Law states that PV=nRT, where P=pressure, V=volume, n=number of moles of gas, R=the relativity constant, and T=temp in Kelvin. According to this law, volume (V) varies as V=(nRT)/P. Using this, we can determine that the volume would normally increase with an increase in the number of moles and/or an increase in the temperature and/or a decrease in pressure. Therefore, we can logically determine that the volume of a gas would decrease in the instance of increasing temperature if either the number of moles of gas was decreased or the pressure was increased (to an extent where the level of volume increase by temperature change has been overcome.)
This equation is applicable: pV=nRTp = 3,8 x 0,082057 x 299/11,3 = 8,25 atmospheres
You can't. Celsius per mmHg is a relationship of temperature to pressure. You can however solve for temperature if you have the value of pressure (e.g. if P= 10 mmHg and V/P = 2 ºC/mmHgthen V= (2 ºC/mmHg)(10 mmHg) = 20 ºC). If you have more information in the problem you might be referring to Gay-Lussac's Law, which compares two values of pressure and temperature to show the relationship (GL'sL: P1/T1 = P2/T2 ... but that would be pressure per unit volume). I'm not sure what you are looking for exactly, but you can't convert temp. to pressure (just like you can't convert feet to lbs.).
Let's see if I have the question correct?Initial volume = 1 mLInitial Temp = 20 oC ie 293 KInitial Pressure = 355 mmHg or 47.3 kPaFinal values -Final volume = ? or unknownFinal Temp = 80 oC ie 353KFinal Pressure = 760 mmHg or 101.3 kPaAssuming the gas is acting as an ideal gas. That is the gas has no extra attraction to other molecules of the gas in the sample.The Gas Law states thatP1V1/T1 = P2V2/T2355 x 1 /293 = 760 x ? /80V2 = 9.5 mL
stp= 22.4 dm3, 1L = 1 dm3 1mole ---> 22.4dm3 xmole ---> 45dm3 45/22.4 = 2.001 moles
if kelvin temp is halved, the volume is halved if pressure is constant.
Increased temperature = increased volume of gas The above answer is non-sense. The pressure could increase with temperature and actually yield a smaller volume... here ya go: The ideal gas law is: PV = nRT, where P = pressure, V = volume, n= number of moles, R = ideal gas constant, T = Temperature in K
You can calculate pressure and temperature for a constant volume process using the combined gas law.
1) Increase in heat 2)Decrease in volume