The concentration is the same !
0.02/5=0.004
Not exactly. Saline solution is sterilized and is a dilution of sodium chloride (NaCl) - meaning that the NaCl is dissolved in deionized water. The solution is 9 grams of sodium chloride (NaCl) dissolved in 1 liter of water.
25ml of the 4M stock solution used
If your solution is a total of 414g and 3.06% of it needs to be NaCl, then you just take 414 x .0306 = grams of NaCl. The rest of the grams will be from other species in the solution.
A 0.0% NaCl solution is a solution with absolutely no NaCl.
2.92%1g=1mL so;2.19/75 = 0.02920.0292*100%= 2.92% NaCl in a solution with total volume of 75 mL
If 10 is 10 molar for you, this is a saturated solution of NaCl.
138 g NaCl 1.10 L= 1100mL 1100mL x 1.08g/mL = 1188 grams TOTAL 138/1188 x 100 = 11.6%
By the definition of molarity, which is mass of solute in moles divided by solution volume in liters, 250 ml of 0.15 M NaCl* solution requires (250/1000)(0.15) or 0.0375 moles of NaCl. Each liter of 2M NaCl solution contains 2 moles of NaCl. Therefore, an amount of 0.0375 moles of NaCl is contained in (0.0375/2) liters, or about 18.75 ml of the 2M NaCl, and if this volume of the more concentrated solution is diluted to a total volume of 250 ml, a 0.15 M solution will be obtained. _________________ *Note correct capitalization of the formula.
Need moles NaCl first. 17.52 grams NaCl (1 mole NaCl/58.44 grams) = 0.29979 moles NaCl =====================Now. Molarity = moles of solute/Liters of solution ( 2000 ml = 2 Liters ) Molarity = 0.29979 mole NaCl/2 Liters = 0.1499 M NaCl ----------------------
Sodium chloride is a salt; the water solution is neutral.
Yes, because the solution of NaCl is an electrolyte.