0
What is the total dissipative power for a 600 Ohm resistor with 75mA flowing?
Wiki User
∙ 8y ago
Ohm's Law: Volts = Amps * Ohms That means that you have 45 volts across the resistor. Power = Volts * Amps That means that you 3.375 Watts going through the resistor.
Alternative Answer
Multiply the square of the current by the resistance.
Wiki User
∙ 8y ago
Add your answer:
Earn +20 pts
A 20 ohm a 60 ohm a 80 ohm resistor are connected in parallel to a 110 volt power source what is the total current flowing in the circuit?
The total current flowing in the three resistors, i = 110 V / r(eq); where r(eq) is the equivalent resistance of the three parallel resistors. r(eq) = 1/[(1/20) + (1/60) + (1/80)] = 1 / 0.079 ohms = 12.63 ohms. i = 110 V / 12.63 ohms = 8.71 amps.
How do you find unknown value of a resistor when total resistor values and voltage are known in a series circuit?
A: If you know the total resistance and total voltage then you know total current flow for the circuit, this current will be same for every resistor in series however the voltage drop will change for each resistor . So measuring the voltage drop across the resistor in question and divide by the total current will give you the resistor value.
When a 10 ohm resistor is connected in parallel to a 15 ohm resistor what percentage of the total current will flow through the 10 ohm resistor?
There will be 20 amps flowing through the 5 ohm resistor. We could do some math and all to figure voltage drops and some other things, but let's cut to the chase and see what's happening. Based on what we know about series circuits and about parallel circuits, we can shred this in nothing flat. So let's. First, we're told 30 amps flows in the circuit. That's the total current, and it will be the current through the first 10 ohm resistor. It has to be. The the 30 amps "splits" to flow through the parallel network of the 10 ohm and 5 ohm resistors. That's 30 amps that has to "split" and some will go through the 10 ohm resistor and some will go through the 5 ohm resistor. With me? Sure. Now for the "trick" here. Since the 5 ohm resistor has only half the resistance of the 10 ohm resistor, twice as much current will flow through it as the 10 ohm resistor. Make sense? Yup. Let's finish this. Since there is twice as much current flowing in the 5 ohm resistor 'cause it's got half the resistance of the 10 ohm resistor, if we have "x" amount of current flowing in the 10 ohm resistor, then we'll have "2x" amps of current flowing in the 5 ohm resistor. That's "3x" amps total, and the "3x" amps equals 30 amps. See through it now? There will be 10 amps flowing through the 10 ohm resistor, and 20 amps flowing through the 5 ohm resistor. Piece of cake.
When you add a resistor to a series circuit what will happen to the total current?
increase.
What are the relations between individual voltages and the total voltages when resistors are connected in series and in parallel?
-- The current in each individual resistor is (voltage across the whole circuit) divided by (the resistance of the individual resistor). -- The current in any individual resistor is less than the total current in the circuit. -- The total current in the circuit is the sum of the currents through each individual resistor.
What is the total current flowing through a 45 ohm resistor (1.4 amps) and a 20 ohm resistor (1.8 amps)?
Just add the amps (3.2 amps).
You are just asking that let us assume you have connected 2 or 3 resistors in a circuit and the current flowing through the circuit and from all the resistors will be same but how?
If the resistors are connected in series, the total resistance will be the sum of the resistances of each resistor, and the current flow will be the same thru all of them. if the resistors are connected in parallel, then the current thru each resistor would depend on the resistance of that resistor, the total resistance would be the inverse of the sum of the inverses of the resistance of each resistor. Total current would depend on the voltage and the total resistance
An electric dc circuit is attached to a 12 volt battery and has a 3ohm resistor in it What is the current flowing through the circuit?
The current depends on the total effecvtive resistance of everything connectedacross the battery.If the resistor is the only component there, then the current is E/R = 12/3 = 4 amperes.
A 5 ohm resistor a 10 ohm resistor and a 15 ohm resistor are connected in series to a 120 volt power source What is the amount of current flowing between the 5 ohm resistor and the 10 ohm resistor?
3.0 or threeAnswerIt depends how they are connected.In series, ther total resistance will be 220 ohms and, so, the current will be 120/220 = 0.545 A.In parallel, ther total resistance will be 20 ohms and, so, the current will be 120/20 = 6 A.
A 20 ohm a 60 ohm a 80 ohm resistor are connected in parallel to a 110 volt power source what is the total current flowing in the circuit?
The total current flowing in the three resistors, i = 110 V / r(eq); where r(eq) is the equivalent resistance of the three parallel resistors. r(eq) = 1/[(1/20) + (1/60) + (1/80)] = 1 / 0.079 ohms = 12.63 ohms. i = 110 V / 12.63 ohms = 8.71 amps.
How do you find unknown value of a resistor when total resistor values and voltage are known in a series circuit?
A: If you know the total resistance and total voltage then you know total current flow for the circuit, this current will be same for every resistor in series however the voltage drop will change for each resistor . So measuring the voltage drop across the resistor in question and divide by the total current will give you the resistor value.
When a 10 ohm resistor is connected in parallel to a 15 ohm resistor what percentage of the total current will flow through the 10 ohm resistor?
There will be 20 amps flowing through the 5 ohm resistor. We could do some math and all to figure voltage drops and some other things, but let's cut to the chase and see what's happening. Based on what we know about series circuits and about parallel circuits, we can shred this in nothing flat. So let's. First, we're told 30 amps flows in the circuit. That's the total current, and it will be the current through the first 10 ohm resistor. It has to be. The the 30 amps "splits" to flow through the parallel network of the 10 ohm and 5 ohm resistors. That's 30 amps that has to "split" and some will go through the 10 ohm resistor and some will go through the 5 ohm resistor. With me? Sure. Now for the "trick" here. Since the 5 ohm resistor has only half the resistance of the 10 ohm resistor, twice as much current will flow through it as the 10 ohm resistor. Make sense? Yup. Let's finish this. Since there is twice as much current flowing in the 5 ohm resistor 'cause it's got half the resistance of the 10 ohm resistor, if we have "x" amount of current flowing in the 10 ohm resistor, then we'll have "2x" amps of current flowing in the 5 ohm resistor. That's "3x" amps total, and the "3x" amps equals 30 amps. See through it now? There will be 10 amps flowing through the 10 ohm resistor, and 20 amps flowing through the 5 ohm resistor. Piece of cake.
What is the total resistance of a 5-ohm resistor and a 10-ohm resistor in a parallel series?
2
What will happen to the other resistor if the number of resistor decreases?
the voltage across that resistor will increase if it is in series with the other resistors. the current through that resistor will increase if it is in parallel with the other resistors.
Is the heat loss and current of a resistor affected by being in a parallel circuit or can you just calculate it the same as in series?
The heat generated by any particular resistor depends (at least electrically) solely on the power it dissipates. Power dissipation in a resistor is equal to current squared times resistance, and the current through the resistor is equal to the voltage across it divided by the resistance. If we take a 10 ohm resistor ('your resistor') and put it in a series circuit such that there is 10 volts across your resistor, the current through it will be 1 ampere (10/10=1). the power dissipated will be 10 watts (1^2 * 10=10). If we put your resistor in a parallel circuit that also puts 10 volts across it, then the current and power will be the same. Your resistor does not know or care where the voltage came from. From this point of view, once you get down to the voltage across the resistor, it does not matter what type of circuit it is in. On the other hand, for any given power supply voltage, then the type of circuit and the value of external components certainly does affect the terminal voltage and thus the current through as well as the power dissipated by the resistor. In a parallel circuit, the voltage across your resistor remains basically the same no matter what resistance you put in parallel with it (unless you overload the power supply or the power supply has high internal resistance). In this case, the voltage across the resistor is the same as the power supply, current is I=E/R, R being that resistor only, and power is P=I^2 * R. In a series circuit the current through the resistors is I=E/R, R being the total resistance (including the other resistor(s)). The power dissipation in your resistor will then be P=I^2 * R, I being the series current we just calculated, and R being your resistor only. Since the other resistors affect the current, and since the current is the same no matter where you measure in a series circuit, then the voltage across your resistor and thus the power dissipation will be affected. The voltage across your resistor will be E=I*R, I being the series current we just calculated, and R being your resistor only. So, while the calculation for power dissipated in a particular resistor does not change relative to what type of circuit it is in, the calculation to arrive at the voltage across the resistor and/or the current through it (which you will then need to calculate power) does. Keep in mind there are other mechanical parameters that influence the actual case temperature of the resistor. Physical size of the case, composition, and airflow velocity, if any, will alter the case-to-ambient thermal conductivity. Ambient temperature will also be a factor in the final temperature.
What watt resistor would you need in a 120 volt circuit with a 100 ohm resistor that has 2 amps load already?
If you connect a 100 ohm resistor across 120 volts it will draw 1.2 amps, amps = E/R. Power = volts x amps so the power required for the resistor would be 120 x 1.2 = 144 watts. It would not matter if the 120 volt circuit already has 2 amps load on it by something else to calculate the wattage of the resistor. The total power on this circuit would be the 144 watts from the resistor and 240 watts from the other 2 amp load (2a x 120v) for a total of 384 watts.
In a parallel circuit each resistor?
reduces the total resiostance
