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in magnetic relays
It experiences a torque but no force. As the dipole is placed at an angle to the direction of a uniform electric field it experiences two opposite and equal forces which are not along the same line. This develops a torque which aligns the dipole along the field. The dipole does not experience any force as the two forces cancel each other.
Hydrogen has a positive charge.
Carbonate (CO3 2-) is trigonal planar with a central C and three O's 120 degrees from each other (D3h symmetry). All the O's have the same electron density because of resonance. This gives carbonate no dipole.
You can view incident IR radiation as an oscillating electric field ( the 'wave-like' view of EM radiation.) As such, it effects the vibration of a molecule by inducing a dipole oscillation of the same frequency. The connection is most clearly seen if you consider that the induced dipole oscillation produces an identical oscillating electric field to the field that induced it. A molecule can only produce an oscillating electric field by vibration if its vibration produces a change in dipole moment (a non-polar molecule would produce a constant electric field regardless of the vibration.) I hope that helps
Zero Dipole would set itself such that dipole moment vector is along the electric field vector
Magnetic dipole is due to two poles of magnet. Electric dipole is due to +ve and -ve charges of electric charges.
yes, there is a NET field .electric dipole experiences a net field .(not in uniform E.Field)
That would have to be when the dipole axis is perpendicular to the field.
The work done by you to turn the electric dipole end for end in a uniform electric field depends on the initial orientation of the dipole with respect to the field. If the dipole is initially oriented such that its positive and negative charges are parallel to the electric field, then no net work is done as the electric field does not do any work on the dipole as the electric field lines do not transfer any energy. On the other hand, if the dipole is initially oriented such that its positive and negative charges are perpendicular to the electric field, then work is done by you to turn the dipole as the electric field exerts a force on the charges in the dipole in opposite directions, causing them to move in opposite directions. As a result, you have to do work to move the charges and turn the dipole.
So interesting query! As we keep the dipole with its dipole moment along the direction of the electric field then it will be in stable equilibrium. IF we keep the same dipole inverted ie its dipole moment opposite to the external field then the dipole will be in unstable equilibrium.
expression for the electric field in the perpendicular bisector plane of a dipole
uses of dipole materials
when angle 0 b/w dipole moment vector p and electric field vector E is zero then potential energy of dipole, U=-pEcos0 =-pE and torque=pEsin0=0;which means that the electric dipole is in stable equilibrium.
dipole dipole
Q1:How to calculate electric potential due to a dipole? Q2:How to calculate electric potential due to ring of charges? Q3:How to calculate electric potential due to charge disk? Q4:how to calculate electric potential due to a quadrupole?
when dipole moment,torque and electric field all the three are perpendicular to each other.