The molar mass of sodium acetate is 82,03. The molar mass of carbon dioxide is 44,01.
This mass is 122 g.
The answer is 18 g water.
The atomic or ionic mass of sodium is 22.99, and the atomic or ionic mass of chlorine is 35.45. A formula unit of sodium chloride contain one ion of each. Therefore, the mass ratio between sodium and chlorine in sodium chloride is 0.649. The mass ratio between 46 and 70 is 0.657. Therefore, chloride is the limiting reactant in this pair. The mass ratio of chloride to sodium chloride is 35.54/(22.99 + 35.54) or 0.607. Therefore, the mass of sodium chloride formed will be 70/(0.607) or 115 gm, where the depressed last digit indicates that it may not be accurate to + 1. (The limiting datum, 70, has only two significant digits.)
NaOH = 22.9898 + 15.9994 + 1.0079 = 39.9971
Sodium "disappears" when it reacts with water because the reaction converts sodium atoms to monovalent sodium cations, which remain in solution in the water as part of the compound sodium hydroxide. As with all other solutions, this one is homogeneous and therefore does not show the presence of solute, but a mass balance would show that the total mass is the same as the sum of masses of the sodium and water reacted, minus of the mass of the hydrogen gas that is formed by reaction and escapes from the solution into the atmosphere.
55.91% The mass of NaSo4 is 142.05 plus the mass of 10 H2O molecules (180.16) is 332.21. Divide the mass o water overthe total mass to get .5591 or 55.91%
Divide the amount of sodium chloride by the total amount (sodium chloride + water). Then multiply that by 100 to convert to percent.
This is (mass of solute) divided by (mass of total solution) expressed as a percentage. The solute is what you are dissolving into the solution. Example: you have 90 grams of water, and you add 10 grams of salt (sodium chloride). The water is the solvent, sodium chloride is the solute, and the solution is salt water. 90 grams + 10 grams = 100 grams (mass of total solution). (10 grams) / (100 grams) = 0.1 --> 10% mass mass percent concentration.
It depends on the mass of the water.
Two Na plus ions will combine with an O2- to form the basic compound sodium oxide. When water is further added, the neutral salt, sodium hydroxide is formed.
Well Sodium Selenide has a formula of Na2Se. Let's take a look at their molecular massesMolecular Mass of Sodium = 22.99=> 2 Sodiums = 45.98gMolecular Mass of Selenide = 78.96=> The Total Molecular Mass is 45.98 + 78.96 = 124.94 g mol-1What does that figure mean?This is the amount of Sodium Selenide that is required to make a 1 mole solution of this substance in a litre of water.
The molar mass of sodium acetate is 82,03. The molar mass of carbon dioxide is 44,01.
This mass is 122 g.
there is no such thing as an average mass of a sodium. sodium is an element. a sodium molecule's mass will therefore be exact in mass, never average.
The answer is 18 g water.
The atomic or ionic mass of sodium is 22.99, and the atomic or ionic mass of chlorine is 35.45. A formula unit of sodium chloride contain one ion of each. Therefore, the mass ratio between sodium and chlorine in sodium chloride is 0.649. The mass ratio between 46 and 70 is 0.657. Therefore, chloride is the limiting reactant in this pair. The mass ratio of chloride to sodium chloride is 35.54/(22.99 + 35.54) or 0.607. Therefore, the mass of sodium chloride formed will be 70/(0.607) or 115 gm, where the depressed last digit indicates that it may not be accurate to + 1. (The limiting datum, 70, has only two significant digits.)