Assuming you meant to write this as a reaction and assuming you meant to ask a coherent question, this is a combustion reaction
CH4+O2 --- CO2+H2O... All that's missing - is the number 2 before the water molecule... CH4+O2 --- CO2+2H2O
Methane , CH4 , is a fuel that can react with O2 to yield CO2, H2O, and heat. CH4 (g) + O2 (g) ----> CO2 (g) + 2 H2O (g) + Heat
The balanced equation is: CH4 + 2 O2 → CO2 + 2 H2O
O2
In carbondioxide: CH4 + 3 O2 ==> CO2 + 2 H2O
Assuming complete combustion: CH4 + 2O2 --> 2H2O + CO2.
Unbalanced CH4 + O2 = H2O + CO2 Balanced CH4 + 2O2 = 2H20 + CO2
CH4+O2 --- CO2+H2O... All that's missing - is the number 2 before the water molecule... CH4+O2 --- CO2+2H2O
Methane , CH4 , is a fuel that can react with O2 to yield CO2, H2O, and heat. CH4 (g) + O2 (g) ----> CO2 (g) + 2 H2O (g) + Heat
Burning, oxidation.
The balanced equation for the combustion of CH4 is CH4 + 2O2 ==> CO2 + 2H2O4 molecules of CH4 will produce 4 molecules of CO2 and 8 molecules of H2O
The balanced equation is: CH4 + 2 O2 → CO2 + 2 H2O
The reactants are CH4, O2 and the products are CO2, H2O. CH4 + 2O2 -> CO2 + 2H2O
3 CH4 + 5 O2 ----> 2 CO + CO2 + 6H2OThe reaction generates quantities of carbon monoxide along with carbon dioxide and water.
This equation is CH4 + 2 O2 => CO2 + 2 H2O.
Make sure atoms on both sides are equal.Balanced equation as follows. CH4+2O2---->CO2+2H2O
The combustion of methane can be balanced in the following manner. One molecule of CH4 plus two molecules of O2 produces one molecule of CO2 plus one molecule of H2O.