It Was an Effect Because,Albert Knew Everythinq Possbibly,And i dont think that anyone would wanna judgee of him o;
In the photoelectric effect, increasing the frequency of incident light increases the kinetic energy of the emitted electrons. This is because higher frequency light photons carry more energy, which can be transferred to the electrons during the photoelectric effect.
In the photoelectric effect, the frequency of incident light determines the energy of the ejected electrons from a material. Electrons are only emitted from the material when the frequency of the incident light is greater than the threshold frequency, which is unique to each material.
Yes - that's how it works.
In the photoelectric effect, the kinetic energy of a photoelectron is directly proportional to the frequency of the incident light. This means that higher frequency light will result in photoelectrons with greater kinetic energy.
photoelectric effect
No, radio waves and microwaves do not produce the photoelectric effect. The photoelectric effect is the phenomenon where electrons are emitted from a material when it is exposed to light of sufficient frequency (typically ultraviolet or higher). Radio waves and microwaves have lower frequencies and energies than light, so they are not capable of causing the photoelectric effect.
Increasing the frequency of light in the photoelectric effect results in the emission of electrons with higher energy levels. This is because higher frequency light carries more energy, which allows electrons to be ejected from the material with greater kinetic energy.
It doesn't, and that's the whole big mysterious fact about the photoelectric effect that was standing Physics on its ear about 100 years ago. It doesn't matter how bright the light is, there's no photoelectric effect if the light is below the threshold frequency. And if it's above the threshold frequency, it doesn't matter how dim the light is, those electrons come streaming off of the surface of the target.
No, the photoelectric effect is the emission of electrons from a material due to the absorption of photons. Infrared rays have lower energy photons than visible light, so they are not typically energetic enough to cause the photoelectric effect. Only photons with enough energy, such as ultraviolet or higher energy photons, can induce the photoelectric effect.
Einstein used the equation E = hf to explain the photoelectric effect, where E is the energy of a photon, h is Planck's constant, and f is the frequency of the light. This equation shows that the energy of a photon is directly proportional to its frequency.
The photoelectric current is directly proportional to intensity.It also depends upon frequency, but frequency more than "THRESHOLD FREQUENCY" does not effect the current.The no. of electrons emitted per second by a photo-sensitive surface is directly proportional to the intensity of the incident radiations.So,the photoelectric current depends upon the intensity of the incident radiations.
The function of a photoelectric material is the energy that a photon of light must possess to just expel an electron from the surface of a material. The work function of cesium is 3.42 x 10^-19 Joules.Ê