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The average equatorial surface gravity on Earth is 0.99732 g
On the moon it is 0.1654 g The numerical constant G that is used in Newton's Law of Universal Gravitation is a constant no matter where you are. (6.67 X 10-11).
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∙ 14y ago
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Why is the value of g more at Jupiter than at earth?
maybe it is bigger in size than the earth.
If an object is moving away from earth what will be value of g?
For every 1% increase in the object's distance from the center of the earth,the value of 'g' in the vicinity of the object decreases almost 2%.
Why can an astronaut on the moon carry a much heavier load than on earth?
people weigh less on the moon that's why astronauts wear heavy equipment ======================================================= Weight, unlike mass, is affected by gravity. As the Moon's gravity is approximately one sixth the Earth's, a person on the Moon would weigh one sixth of what they weigh on Earth. Their mass, however, would stay the same.
Upon what factors value of g depends?
Gravitational acceleration (g) depends on the mass of the object that you are being accelerated toward (Earth), and the average distance from that object. (the radius of the Earth)
Force of gravity here has less than half the pull exerted by gravity on earth?
Gravity (g)= (GM)/R^2, where G = Universal gravitational constant, whose value is 6.67 X 10^(-11) NM^2/kg^2; M = Mass of heavenly body and R = Radius of heavenly body. Now, As the radius of moon is accordingly less than the radius of the earth, the square of radius will be very less and the mass is also lesser than that of earth, so it won't affect so much. Hence, The moon's gravity is one sixth of earth's gravity as Radius of moon is 1738 km, whereas the radius of Earth is 6371 km, and mass of earth is 6 × 10^24 and mass of moon is 7.36 × 10^22 kg.
How would the time period of a simple pendulum clock be affected if it were on the moon instead of the earth?
The time period of a pendulum would increases it the pendulum were on the moon instead of the earth. The period of a simple pendulum is equal to 2*pi*√(L/g), where g is acceleration due to gravity. As gravity decreases, g decreases. Since the value of g would be smaller on the moon, the period of the pendulum would increase. The value of g on Earth is 9.8 m/s2, whereas the value of g on the moon is 1.624 m/s2. This makes the period of a pendulum on the moon about 2.47 times longer than the period would be on Earth.
Value of gravitational constant on earth and moon?
It's the same as that of Earth but the value of g varies from one object to the other. The value of the gravitational constant or the BIG "G" remains constant. I think you confused it with the LITTLE "g" which is the gravitation of a object (one with mass) or the acceleration due to gravity. The value of g on Earth and Moon is 9.8m/s^2 and 1.6249m/s^2, respectively. I hope this answers you all.
Value of g in universe?
I think that g (the gravitational constant) varies dependent on your proximity to other massive bodies. For example the value of g on the moon is less than the value of g on earth. It is not constant throughout the universe.
What is the ratio of natural frequency on earth to moon?
The ratio of natural frequency of earth to moon can be given by the under-root of their value og 'g' as the formula for natural frequency can be write as "under root of g/delta"...
Why has the earth got gravity and the moon has not?
Basically the question is wrong or the concept of gravity in your brain is wrong, as gravity exists both at moon and earth, but the value of "g" varies as at earth it is 9.81m/s^2, and at moon it is some what around 1.8m/s^2.
What is the density of the Earth's moon?
The density of the Earth's moon is 3.3464 g/cm3 (or 3346.4 kg/m3).
What happens to the objects weight when it travel's to the moon?
weight is defined as the force acting on a body in a gravitational field, so it is can be written asW = mg where m is the mass of the body and g is the acceleration due to gravity.On earth g has a value of approx. 9.81 ms-2 whereas on the moon the value of g is approx. 1.7ms-2. So the weight of an object decreases by a factor of 1/6th of its original value when taken on the moon.
What is the value of 'g' if the earth stops rotating?
i think value of g becomes zero
What is the mass of something on earth that weighs 39 newtons on the moon?
W = mgLet G be Earth's acceleration due to gravity.mass (m) of the object is constant.Therefore weight on earth :W = mG-> W = 9.8m ....(substituting G by its universal value)Gravitation on Moon : G/6Weight on Moon :W1 = mG/6->W1 = 1.6mAs given : 1.6m = 39=> m = 390/16=> m = 24.375 kgsTherefore weight on earth = (9.8 x 24.375) newtons= 238.875 NAns. 238.875 Newtons is the weight24.375 is the mass.
What is the periodic time of a 0.5m pendulum on the moon?
note: (g(moon)= 1/6g(earth))
What is the value of G at center of earth?
Zero.
What is the value of 'g' at center of earth?
Zero.
