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Joule-Thompson coefficient for methane

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Q: What is the value of joule Thomson coefficient for Natural gas?
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we all know determining the joule thomson coefficient is determined by performing irreversible adiabatic process, i.e. constant enthalpy process, it may be determined foe any gas .Since enthalpy remains constant in this processlet h1 be the enthalpy before the irreversible expansion and h2 be the enthalpy after expansion, h1=h2 . for a real gas h enthalpy is a function of pressure and temperature so it may get cooled or get warm according to nature of gas and conditionsbut for an ideal gas h=f(T) only since h= u +pv [they both are dependent on absolute temperature] so while going through irreversible expansion the gas does not depend on pressure .mathematically,let @ be joule thomson coefficient$ be parial derivative@= 1/ cp multiplied by [T multiplied by{$v/$t}at constant pressure -v]for an ideal gas $v/$T at constant pressure becomes v/T also pv =RT {observe equations are written on per kg basis} so v/T= R/p so we get @=0


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