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What is tje velocity of a ball thrown upward at 16 ft/sec?
If a ball is thrown vertically upward with a velocity of 160 ft/s, then its height after t seconds is s = 160t - 16t^2. If a ball is thrown vertically upward with a velocity of 160 ft/s, then its height after t seconds is s = 160t − 16t^2.
What is the velocity of a ball thrown upward at 16 feet per second?
About 11 miles per hour.
What is the accelleration due to gravity?
16 ft./sec./sec.
The impulse given to a ball with mass of 4 kg is 16 Nsec If the ball starts from rest what is its final velocity?
An impulse is simply a change of momentum, and momentum is defined as mass x velocity; so you just divide the momentum by the mass to get the velocity. Note about the units: newton x second is the same as kilogram x meter/second2.
What must be held constant if uniformly accelerated motion is to take place?
To ensure uniformly accelerated motion, the net force acting on the object must be constant. This means that there should be no change in the magnitude or direction of the net force throughout the motion. Other factors such as mass and friction should also be kept constant.
What is tje velocity of a ball thrown upward at 16 ft/sec?
If a ball is thrown vertically upward with a velocity of 160 ft/s, then its height after t seconds is s = 160t - 16t^2. If a ball is thrown vertically upward with a velocity of 160 ft/s, then its height after t seconds is s = 160t − 16t^2.
What is the velocity of a ball thrown upward at 16 feet per second?
About 11 miles per hour.
What is the velocity of a ball thrown at 16 feet per second?
16 feet/second is the speed. To know the velocity, you would also need to specify the direction in which the object moves.
If a ball is thrown into the air with a velocity of 38 ft per sec its height in feet after t seconds is given by y equals 38t minus 16t2 Find the velocity when t equals 2?
Substitute the 2 in for t.38(2)-16(2)^276-64=12
How many times have teams thrown the ball to Nnamdi Asomugha?
only about 25 times in 16 games in 2008.
A ball thrown horizontally from a cliff and hits the ground 4 seconds later 40 meters from the base of the cliff How high was the cliff?
If it was thrown horizontally, it had an initial velocity of 10 meters/sec parallel to the ground. (It traveled 40 meters in 4 secs with no acceleration. x=vt) It also took 4 secs to travel vertically. It started with a vertical velocity of 0 m/s. Using x=v0 + (1/2) a t2 a = -g ( Acceleration due to gravity 9.8m/s2) x=0-(1/2)g*16 = -8 * 9.8 = -78.4 m It fell 78.4 meters before coming to a stop.
What is the accelleration due to gravity?
16 ft./sec./sec.
What one dose this to a bowling ball to knock down the pins?
First Answer:Yes it does.Second Answer:Not so much. The most important thing is velocity, tracking, rotation, accuracy, and hitting the sweet spot or "pocket" of the pins. You will get more pin action from 16 pound ball than a 6 pound ball thrown with the same velocity though, so in broader general terms yes, but not from just a difference in a few pounds alone.
The impulse given to a ball with mass of 4 kg is 16 Nsec If the ball starts from rest what is its final velocity?
An impulse is simply a change of momentum, and momentum is defined as mass x velocity; so you just divide the momentum by the mass to get the velocity. Note about the units: newton x second is the same as kilogram x meter/second2.
If a ball is thrown at an angle of 40 degrees above the horizontal at a speed of 16 meters per second from the top of a 12.4 m tall building what is the maximum height of the ball above the ground?
17.8 meters
When was Thrown into the Fire created?
Thrown into the Fire was created on 2009-12-16.
If a 2kg metal ball hits a 1kg wooden ball at a speed of 3ms and the metal ball continues at a speed of 1ms how fast is the wooden ball going?
This question is all about kinetic energy. Kinetic Energy = 0.5 * mass * velocity^2 Firstly we must assume that no energy is lost to heat and sound, so that kinetic energy is constant throughout the contact. The initial kinetic energy is all in the 2kg metal ball. Using the above formula we find that the energy is 0.5 * 2 * 3^2 = 0.5 * 2 * 9 = 9 J The final kinetic energy must be the same (because of our assumption). The metal ball has a kinetic energy of 0.5 * 2 * 1^2 = 1 J, so the wooden ball must have the remainder, which is 8 J. 8 = 0.5 * 1 * velocity^2 velocity^2 = 16 velocity = square root of 16 velocity = 4 m/s
