If you mean that you throw the ball or the rock vertically and it gets no more boost
after that, then the required vertical launch speed is 99 meters per second.
Check:
-- Time for speed to dwindle to zero is 99/9.8 seconds .
-- Average speed during that time is 99/2 .
-- Distance = (average speed) x (time) = (99/2) x (99/9.8) = 500.051 meters. Close enough!
Time taken: 4.06 seconds.Final velocity: 42.8 m per sec.
The time taken by the ball to reach the maximum height is 1 second. The maximum height reached by the ball is 36 meters.
It takes 5 seconds to reach the top of its path.
If we can ignore the effects of air resistance and consider gravity only, then thehorizontal component of velocity has no effect on the vertical component.These balls accelerate vertically at the same rate, and hit the ground at the same time.In an extreme case, the same is true of a shot fired from a gun and one dropped fromthe muzzle at the same time.
Its the air resistance that causes the free falling body to reach its terminal velocity
No. What counts in this case is the vertical component of the velocity, and the initial vertical velocity is zero, one way or another.
It will fall with increasing velocity due to gravity and reach the peak velocity just before hitting the ground.
The maximum height the water will reach is 157 m.
when the object reaches maximum height, the velocity of the object is 0 m/s.It reaches maximum height when the gravity of the body has slowed its velocity to 0 m/s. If there is no gravity and there is no external force acting on it then it will never reach a maximum height as there wont be a negativeaccelerationdemonstrated by newtons first law.Where there is and you have the objects initial velocity then you can use :v^2 = u^2+2.a.sv = Velocity when it reaches Max. height so v = 0u = Initial Velocity (m/s)a = Retardation/ Negative Acceleration due to gravity, -9.80m/s ^2And then the unknown (s) is the displacement, or height above ground, and if everything else is in the right format it should be in metres.
Time taken: 4.06 seconds.Final velocity: 42.8 m per sec.
The time taken by the ball to reach the maximum height is 1 second. The maximum height reached by the ball is 36 meters.
If you ignore air resistance, then they will reach their maximum height at the same time. In order not to ignore air resistance, you would need to know their shapes.
Acceleration = (change in velocity) / (time for the change)9.8 = (change in velocity) / (2 seconds)9.8 x 2 = change in velocity = 19.6 meters per second .Hint: The mass of the object and the height of the building are there just tothrow you off balance. You don't need either of them to answer the question.
12.6 meters 0.1 bar is gained for every meter.
It takes 5 seconds to reach the top of its path.
If we can ignore the effects of air resistance and consider gravity only, then thehorizontal component of velocity has no effect on the vertical component.These balls accelerate vertically at the same rate, and hit the ground at the same time.In an extreme case, the same is true of a shot fired from a gun and one dropped fromthe muzzle at the same time.
Its the air resistance that causes the free falling body to reach its terminal velocity