The voltage between point p and the battery is not able to measured exactly. You can never measure the absolute electric potential at any point. its just not possible. That is why we talk about difference in potential.
The power of a battery is typically measured in voltage (V) and current (A). The voltage represents the electrical potential difference between the positive and negative terminals, while the current represents the rate of flow of electricity. The power output of a battery is the product of voltage and current (P = V x I).
in ac circuits power,P=VICOS@ @ is the angle between voltage and current. in dc P=VI V is the voltage I is the current. Power (in Watts) is current (A) x voltage (V)
Answer #1:56watt = 56000mw,1000milliamp = 1amp,watt = amp x volt = watt/volt,if the battery is rated 11.1v,so 56000mw/11.1v = 5 045.04505mah==============================Answer #2:Answer #1 has a big ' if ' hidden in it.In general, 56 Wh = 56,000/voltage of the battery mAh and for ANY number of Wh ... call it ' P ' ...P Wh = 1,000 P/battery voltage mAh .
The unit of power is watts, the unit of current is amps, and the unit of voltage it volts. Power = Voltage X Current Voltage = Power / Current Current = Power / Voltage In electricity, power is symbolized with a P, current with an I, and voltage with a V. The real formula looks like: P = V x I V = P / I I = P / V
In semiconductors, the relationship between the flow of electrical current and electrostatic potential across a p-n junction depends on a characteristic voltage called the thermal voltage, denoted VT.
Clippers are diode, wave-shaping circuits. The output of clipping circuits looks like a portion of the input signal is clipped off, kind of like a limiter. A clipping circuit requires at least two basic components, a simple diode and a resistor. The output wave form can be clipped at different levels by interchanging the position of the diode and or resistor, and changing the voltage of the dc battery.
Making a circuit? Sorry, but its not entirely clear from your question what you are asking about. Also depending on battery voltage and polarity, the junction may or may not be destroyed.
Scroll down to related links and look at "Electrical voltage V, amperage I, resistivity R, impedance Z, wattage P".
P = I^2 R = IV = v^2 / R , Where P is power, I is current, R is resistance, and V is voltage. Given voltage and current, power = current * voltage, or P = IV.
Power (P) = Voltage (V) x Amperage (I) Written as P=VxI or to find Voltage V=P/I Voltage is measured in Volts (V) Amperage is measured in Amperes (Amps or A) Power is measured in Watts (W)
Knee voltage (cut in voltage) :-The forward voltage at which the current through the P-N Junction starts increasing rapidly is called as Cut in voltage or knee voltage Breakdown voltage :-It is the minimum reverse voltage at which the P-N Junction can conduct without damage to the current
P=VI => I=P/V => I=60W/12V => I=5A 5 amps when the globe is operating