Lambda( Wavelength) = velocity/frequency
Frequency = 18 x 10^3 Hz
Velocity = Speed of sound = 340m/s
wavelength = 340/18x10^3 = 17/900 m
If the high frequency sound is within hearing range, you can hear it as a high-pitched sound. If it's out of the hearing range you can't hear it, of course.
Formula is velocity=frequency X wavelength so Wavelength = 5m
the frequency of a sound wave is higher if its wavelength is shorter
Frequency= 226.67 Yes, we can hear this sound.
Wavelength.
If the high frequency sound is within hearing range, you can hear it as a high-pitched sound. If it's out of the hearing range you can't hear it, of course.
To find the wavelength, the following formula applies: λ = ν / f That in common words is: Wavelength = Wave's Speed / Wave's Frequency So, Wavelength of sound wave = Speed of sound wave / Frequency of sound wave Now, Speed of sound wave is 343 m/s, so Wavelength of sound wave = 343 m/s / Frequency of sound wave Frequency of sound waves audible to a human ear range between 20 Hz to 20 kHz. So filling the desired sound frequency in the equation above you get the desired wavelength of that sound wave.
Infrasound has a frequency below normal hearing. Ultrasound waves have a frequency above the normal range of human hearing.
There are two parameters regarding hearing ranges. One is frequency range, and the range of hearing is measured in Hertz, which is cycles per second. Another variable is the threshold of hearing. In other words, how loud does a sound at a given frequency have to be to be heard. That sound level is measured in decibels with respect to a reference level. The threshold level will vary with the pitch (frequency) of the sound, as you might have guessed.
The amplitude of a sound is not related to its frequency (wavelength).There might appear to be a connection if the listener's hearing is more or less sensitive to certain frequencies. For example, as a sound with constant amplitude rises in frequency toward the upper limit of the listener's hearing range, it will be perceived as if its amplitude (loudness) is dropping, although that sensation is in the ear of the beholder and not a property of the sound itself.
White noise
It just is. Sound behaves like a wave, and the pitch of the sound affects the wavelength. And wavelength is directly related to the frequency. A high pitched sound has a a shorter wavelength and a higher frequency than a low-pitched sound.
No. The amplitude of a sound is not related to its frequency (wavelength).There might appear to be a connection if the listener's hearing is more or less sensitive to certain frequencies. For example, as a sound with constant amplitude rises in frequency toward the upper limit of the listener's hearing range, it will be perceived as if its amplitude (loudness) is dropping, although that sensation is in the ear of the beholder and not a property of the sound itself.
Kind of. The pitch of a sound wave is its frequency, and because frequency = 1 / wavelength its pitch is related to the wave length. So to answer, no, the pitch of sound is not the wavelength itself, rather it is the inverse of the wavelength ( 1/wavelength)falseACJM
If you change sound's frequency and hold the velocity constant, the sound's wavelength also changes. If you change sound's frequency and keep the wavelength constant, then velocity also changes.
That would also depend on the speed. Note that sound can go at quite different speeds, depending on the medium and the temperature. Use the formula speed (of sound) = frequency x wavelength. Solving for wavelength: wavelength = speed / frequency. If the speed is in meters / second, and the frequency in Hertz, then the wavelength will be in meters.
The level of the sound or the amplitude of the sound has nothing to do with the wavelength. Speed of sound c = wavelength λ × frequency f.