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When one object exerts a force on another object, the second object the same size force on the first object.
Below is the solution using eculator(Find Pressure from Area, Force.)Using the expression(see reference): P = F/Awhere:F is the Force = 60 NA is the Area = 20 m²we calculate the value for Pressure(P):P = 60/20∴ P = 3.0Final Answer :3.0 Pascal
Strictly, kg (kilogrammes) is a unit of weight rather than mass, which is measured in N (Newtons). This is important, because the MASS of an object does not change, whereas its WEIGHT does change according to the gravitational pull it is experiencing. On earth 1kg is about 10N. On the moon, say, something weighing 1kg would have a MASS of a little over 60N. If we change the word 'mass' in your question to 'weight', then the answer would be 'anything greater than 5kg'. If not, then 'anything greater than 50N subject to gravitational forces on the Earth's surface'. An object's INERTIA is the force that must be overcome in order to change its position (if stationary): so, it is clearly easier to move a 5kg object than it is to move any object that is heavier.
An object on the moon's surface weighs 0.165 as much as it does on the Earth's surface.
The object's acceleration is 1.33m/s2 (A = force/mass).
When one object exerts a force on another object, the second object the same size force on the first object.
Work = (Force) x (Distance) = 60 x 5= 300 Newton Meters = 300 Joules
work is force by displacement. So 20x4 is 80J. However, your units of work are not correct. It is either newton metres or Joules, so the rest cannot be calculated. (effecuency here would be what work is actually done / what was spent doing the work x100 (for %)
875.634176 kilograms ==
W=Fd W=(60N)(4m) W=240J
If the speed is constant the frictional force must be equal to the propelling force (which is gravity in this case) as any imbalance of forces creates an acceleration. If the 60N is in the same direction as the movement, then the frictional force is also 60N. If 60N is the gravitational force, you'll have to use the angle to calculate the propelling force that acts in the direction of movement. Again, the frictional force will be exactly the same as the propelling force in the direction of movement (only in magnitude, though - the direction of the frictional force (the vector) will be in the opposite direction).
F = ma(60N) = (10kg)a a = 60N / 10kga = 6 N / kga = 6m/s^2
It depends on the direction of the two forces. If the two forces are in the same direction, the net force would be 60N or -60N. If the two forces are in opposite directions the net force would be either 30N or -30N.
60N and 20
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