Im assuming you mean Mg(OH)2 and not MgOHThe reaction between Mg(OH)2 and HCl is as follows: Mg(OH)2 (aq) + 2HCl (aq) -> MgCl2 (aq) + 2H2O (l)First the number of mole is found: n(HCl) = c × v = 0.100M × 0.200L = 0.0200mol (to 3 significant figures)Next we find the number of mole of Mg(OH)2:n(Mg(OH)2) ÷ n(HCl) = Coefficient of Mg(OH)2 ÷ Coefficient of HCl n(Mg(OH)2) ÷ n(HCl) = 1 ÷ 2 therefore:n(Mg(OH)2) = (1 ÷ 2) × n(HCl) n(Mg(OH)2) = (1 ÷ 2) × 0.0200moln(Mg(OH)2) = 0.0100mol (to 3 significant figures)Finally we calculate the volume of Mg(OH)2 reacted:v(Mg(OH)2) = n ÷ cv(Mg(OH)2) = 0.0100mol ÷ 0.500MThereforev(Mg(OH)2) = 0.0200L (to 3 significant figures) = 20.0ml (to 3 significant figures)
MgCl, H2O and CO2 are produced in a reaction between HCL and MgCO3.
Mg(OH)2 HCl
Magnesium + Hydrochloric acid ----> Magnesium Chloride + HydrogenMg + 2 HCl -----> MgCl2 + H2
Mg + 2HCl => H2 + MgCl2 The type of chemical reaction is a Single Replacement.
100 mL 5.0 M HCl solution (0.50 mol HCl) is sufficient to fully react with 3.00g Mg, which is 3 (g) / 12 (g/mol) = 0.25 mol Mg because it needs a molar '1 to 2' ratio with HCl:(1) Mg + 2 HCl --> Mg2+ + H2 + 2 Cl-
2 HCl + Mg(OH)2 ----> MgCl2 + 2H2O
Mg + 2 HCl = MgCl2 + H2
2HCl + Mg(OH)2 ------> H2O + MgCl2
The balanced equation is as follows: Mg + 2HCl --> MgCl2 + H2
First, the correct formula for Magnesium hydroxide is Mg(OH)2 The reaction goes Mg(OH)2 + 2HCl --> MgCl2 + 2H2O
Mg(s) + 2 HCl(aq) --> 2 MgCl2(aq) + H2(g)