PV = nRTV = nRT/P = (2moles)(0.0821 Latm/Kmol)(300K)/1.3 atm
V = 37.9 liters = 38 liters (2 significant figures)
38 L
38 L
V = nRT/p : v = 160*0.08205*300/2 =1.97mL
38L
38 L
38 L
The amount of oxygen is 0,067 moles.
The pressure is 20,68 at.
Pressure, volume, temperature & the amount of gas.
The number of moles is 0,579.
38 L
38 L
38 L
The amount of oxygen is 0,067 moles.
54 liters at STP (standard temperature and pressure)
0.48 liters at STP (standard temperature and pressure)
The volume occupied by 3 moles of nitrogen gas will be different, depending on the temperature and pressure of the gas.
The volume of one mole of gas at a standard temperature and pressure is 22.4 liters. Multiply 22.4 liters by 0.25 moles to get a volume of 5.6 liters.
The volume occupied by 2.12 moles of nitrous oxide is 9.35. A mole is described in chemistry as an amount of pure substance containing the same number of chemical units as there are atoms.
This volume is 6,197 399 5 at 25 0C.
The pressure is 20,68 at.
8.96 cm3