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What is the name of this compound NaCO3 x 10H2O?
Sodium carbonate x water --> sodium carbonate (in solution)--> Sodium Carbonate Decahydrate
How value of x can be calculated in the formula Na2CO3?
With great difficulty - since there is no x in Na2CO3.
What is the molecular weight of Na2CO3?
The molecular weight of Na2CO3 is: (2 X 23) + 12 + (3 X 16) = 106
What is the chemical formula for decahydrate?
Formula: X.7H2OX is a compound
What is the KB of Na2CO3?
The molar mass of Na2CO3 (sodium carbonate) is approximately 105.99 g/mol. To calculate the KB, you would first look up the pKa values for the conjugate acid (HCO3-) and then use the relation KB = Kw / Ka.
What is the percentage of water to the nearest tenth in this compound Na2CO3 x 10H2O?
there are 159.6g of cupric sulfate and 90.1g of waters63.5gCu+32.1gS+(16.0*4)gO=159.6gCuSO4 5(1.01*2)gH+5(16.0)gO=90.1g5H20 therefore, the gram formula mass is 249.7g the percent composition of water is 36.1%((90.1g)/(249.7g))*100% p.s.-my basic math skills suck so you may want to take the given values and crank them through the equation to check Your math is correct. I ran the problem myself and got the same answer. We even did this as a lab in Chemistry class and I got near the same answer (35% in an unregulated test).
What is the mass percent of sodium in Na2CO3 the molar mass of Na2CO3 is 106gmole?
The molar mass of Na2CO3 is 106 g/mol. The molar mass of sodium in Na2CO3 is 2 * 23 g/mol = 46 g/mol. To calculate the mass percent of sodium in Na2CO3, we divide the molar mass of sodium by the molar mass of Na2CO3 and multiply by 100: (46 g/mol / 106 g/mol) * 100 ≈ 43.4%.
How many grams are in 0.577 mol Na2CO3?
To convert moles to grams, you need to multiply the number of moles by the molar mass of the substance. The molar mass of Na2CO3 (sodium carbonate) is 105.99 g/mol. So, to find the grams in 0.577 mol of Na2CO3, you would calculate 0.577 mol * 105.99 g/mol = approximately 60.98 grams of Na2CO3.
How many grams of NaOH are formed from reacting 120g sodium carbonate with excess calcium hydroxide?
Write out the equation, and remember to balance each side.Na2CO3 + Ca(OH)2 --> 2NaOH + CaCO3Molecular WeightsNa2CO3: 106 grams/moleNaOH: 40 grams/moleAlways convert your reagents into moles.(120g Na2CO3) x (1 mole Na2CO3/106 grams Na2CO3) = 1.132 molesAccording to the balanced equation, 1 molecule of Na2CO3 generates 2 molecules of NaOH.(1.132 moles Na2CO3) x (2 moles NaOH/1 mole Na2CO3) = 2.264 moles NaOHNow determine the number of grams from 2.264 moles of NaOH.(2.264 moles NaOH) x (40 grams/ 1 mole NaOH) = 90.57 grams NaOH formed.To prevent rounding off too many times, carry out the dimensional analysis in one step:(120g Na2CO3) x (1 mole Na2CO3/106 grams Na2CO3) x(2 moles NaOH/1 mole Na2CO3) x (40 grams/ 1 mole NaOH) = 90.57 grams NaOH
How many moles of washing soda are there in 5g?
Washing soda is sodium carbonate, Na2CO3. Using the atomic weights from the periodic table and the subscripts in the formula, the molar mass of Na2CO3 = 106g/mol. 5g Na2CO3 x (1mol Na2CO3/106g/mol) = 0.05mol Na2CO3
How many grams of HCL needed to react with 4000 g of Na2co3?
First write don the BALANCED reaction eq'n 2HCl(aq) + Na2CO3(aq) = 2NaCl)aq_ + H2O(l) + CO2(g) Note the molar ratios are 2:1 ::2:1:1 So two moles of HCl reacts with one mole of sodium carbonate . Next we need to convert 4000 g to moles. Using the Periodic Table and the Atomic Weights. 2 x Na = 2 x 23 = 46 1 x C = 1 x 12 = 12 3 x O = 3 x 16 = 48 Adding for one molecule(Na2CO3) = 106 Hence moles (Na2CO3) = 4000 / 106 = 37.735849 moles. This is equivalent to 1 molar ratio above. Hence moles (HCl) = 2 x 37.735849 = 75.471698 . This is equivalent to 2 molar ratios above. Hence Mass (HCl) is 75.471698 = mass(g) / 36.5 (The Mr of HCl). mass (g) = 36.5 X 75.471698 = 2754.71698 g. ~ 2.755 kg.
A chemist requires 0.277 mol Na2CO3 for a reaction. How many grams does this correspond to?
0.277 mole Na2CO3 x 106 g/mole = 29.4 g (to 3 significant figures)
