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Six carbon dioxide molecules (CO2) are required to create one glucose molecule (C6H12O6) because carbon dioxide has one carbon per molecule, while glucose molecules have six carbons.
15 litres
64 net...68 are produced overall but 2 ATP's are used in the reaction per molecule of glucose.
Glucose will caramelize if you autoclave it on a cycle that runs more than 15 minutes. However you may still get a brown tinting of the media.
Nitrogen, N2
A bunch of glucose molecules joined by glycosidic bonds forms either glycogen or starch, depending on the way they are bonded together, i.e. depending on the nature of the glycosidic bond.
Six carbon dioxide molecules (CO2) are required to create one glucose molecule (C6H12O6) because carbon dioxide has one carbon per molecule, while glucose molecules have six carbons.
Let's start by setting up an equation of what is going on chemically. Sucrose is a sugar dimer of 1 fructose and 1 glucose molecule, so: 1 Sucrose --> 1 Glucose + 1 Fructose So, what we need to do from here is calculate how many moles of glucose would be needed to make 1 microgram (ug). The atomic mass of glucose is 180.16 g/mol, so 1ug = .000001 g. 0.000001g divided by 180.16 g/mol = 5.55 X 10^9 moles. Avogadro's number is 6.02214 X 10^23 and represents how many molecules are in 1 mole of a substance. Multiply this number by the moles of glucose and we should get 3.34 X 10^15 molecules in 1 microgram of glucose. Since the decomposition of 1 molecule of sucrose liberates 1 molecule of glucose, we do not have to take into account stoichiometric ratios. So, we need 3.34X 10^15 molecules of sucrose to decompose to get the same number of molecules of glucose. If we divide this by 1 million, we get 3.34 x 10^9. This is the number of seconds that would be needed for the decomposition to take place. Divide that by 60 we get 5.57 X 10^7 minutes, divide by 60 again and we get 9.28 X 10^5 hours, divide by 24 and we get 38,684 days and finally divide by 365 to get just under 106 years!
15
The number of molecules in 15 g ethane is approx. 3,011.10e23.
The normal glucose concentration in urine ranges from 0 to 15 mg/dL. The glucose concentration in urine becomes zero when no glucose has spilled over into the urine.
15 litres
i know it's higher than corresponding blood glucose concentration from 10 - 15%
15
9033212250000000000000000 molecules or, in scientific notation, 9.03321225 × 10^24 molecules. This is found by multiplying the number of moles by the number of molecules in a mole, which is avagadro's number, 6.0221415 × 10^23. The calculation is: 15 × (6.0221415 × 10^23)
64 net...68 are produced overall but 2 ATP's are used in the reaction per molecule of glucose.
360 calaries